Question

如何将Restrictions.in与列表字段一起使用？

这是我的模特：

@Entity
@Table(name = "W_GROUP", schema = "U_FRONTEND")
public class UserGroup {
@Id
@Column(name = "GROUP_ID")
private Long id;

@Column(name = "NAME", length = 100, nullable = false, unique = true)
private String name;

@ElementCollection(targetClass = Feature.class)
@JoinTable(name = "W_FEATURE", joinColumns = @JoinColumn(name = "GROUP_ID", nullable = false), schema = "U_FRONTEND")
@Column(name = "NAME", nullable = false, length = 50)
@Enumerated(EnumType.STRING)
private List<Feature> features;

@JoinTable(name = "W_USER_GROUP", joinColumns = @JoinColumn(name = "GROUP_ID"), inverseJoinColumns = @JoinColumn(name = "USER_ID"), schema = "U_FRONTEND")
@ManyToMany
private List<User> users;

@Column(name = "UPD_USER", nullable = false, length = 50)
private String updUser;

@Column(name = "UPD_DATE", nullable = false, columnDefinition = "date")
private Calendar updDate;
// Getters and setters
}

我试图只获得具有某些功能的群组：

Criteria criteria = session.createCriteria(UserGroup.class);

            criteria.addOrder(new Sort(Order.ASC, "name").getOrder());

            criteria.add(Restrictions.not(Restrictions.in("features",
                    FeatureUtils.getInvalids())));

但这会返回错误：

引起：org.hibernate.exception.GenericJDBCException：缺少IN或索引:: 1处的OUT参数 org.hibernate.exception.internal.StandardSQLExceptionConverter.convert（StandardSQLExceptionConverter.java:54）在 org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert（SqlExceptionHelper.java:125）在 org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert（SqlExceptionHelper.java:110）在 org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation（AbstractStatementProxyHandler.java:129）在 org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke（AbstractProxyHandler.java:81）在$ Proxy35.executeQuery（未知来源）at org.hibernate.loader.Loader.getResultSet（Loader.java:1926）at at org.hibernate.loader.Loader.executeQueryStatement（Loader.java:1727）在org.hibernate.loader.Loader.doQuery（Loader.java:852）处 org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections（Loader.java:293）在org.hibernate.loader.Loader.doList（Loader.java:2411）at org.hibernate.loader.Loader.doList（Loader.java:2397）at org.hibernate.loader.Loader.listIgnoreQueryCache（Loader.java:2227）at at org.hibernate.loader.Loader.list（Loader.java:2222）at org.hibernate.loader.criteria.CriteriaLoader.list（CriteriaLoader.java:122）在org.hibernate.internal.SessionImpl.list（SessionImpl.java:1621）at org.hibernate.internal.CriteriaImpl.list（CriteriaImpl.java:374）at at hamburgsud.frontend.dao.UserGroupDAO.list（UserGroupDAO.java:39）at at hamburgsud.frontend.controller.UserController.form（UserController.java:38） at sun.reflect.NativeMethodAccessorImpl.invoke0（Native Method）at sun.reflect.NativeMethodAccessorImpl.invoke（NativeMethodAccessorImpl.java:39）在 sun.reflect.DelegatingMethodAccessorImpl.invoke（DelegatingMethodAccessorImpl.java:25）在java.lang.reflect.Method.invoke（Method.java:597）at br.com.caelum.vraptor.interceptor.ExecuteMethodInterceptor.intercept（ExecuteMethodInterceptor.java:61） ... 43更多引起：java.sql.SQLException：缺少IN或OUT index :: 1处的参数 oracle.jdbc.driver.DatabaseError.throwSqlException（DatabaseError.java:112）在 oracle.jdbc.driver.DatabaseError.throwSqlException（DatabaseError.java:146）在 oracle.jdbc.driver.OraclePreparedStatement.processCompletedBindRow（OraclePreparedStatement.java:1681）在 oracle.jdbc.driver.OraclePreparedStatement.executeInternal（OraclePreparedStatement.java:3280）在 oracle.jdbc.driver.OraclePreparedStatement.executeQuery（OraclePreparedStatement.java:3329）在 com.mchange.v2.c3p0.impl.NewProxyPreparedStatement.executeQuery（NewProxyPreparedStatement.java:76） at sun.reflect.NativeMethodAccessorImpl.invoke0（Native Method）at sun.reflect.NativeMethodAccessorImpl.invoke（NativeMethodAccessorImpl.java:39）在 sun.reflect.DelegatingMethodAccessorImpl.invoke（DelegatingMethodAccessorImpl.java:25）在java.lang.reflect.Method.invoke（Method.java:597）at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation（AbstractStatementProxyHandler.java:122） ... 63更多

Answer 1

我知道它不是很漂亮，但你可以构建一个id列表（List<Long> featureIds），然后做一个：

Restrictions.in("features", featureIds);

使用带有List <enum> </enum>的Hibernate Restrictions.in

1 个答案: