我有sqlite数据库,数据库格式是
表名=主项目
column 0(M_ID) column 1(M_ISSUE)
M1 i1
M1 i2
M1 i3
M2 x
M2 y
M2 z
M3 1
M3 2
在上表中,我需要显示M_ID问题计数,(例如: - M_ID(M1)有3个问题(i1,i2,i3),如明智的M2和M3。
这是我的源代码
for (int i = 0; i < [masterProjIDArray count]; i++)
{
MySQLite *sqlobj = [[MySQLite alloc] initWithSQLFile:@"myDb"];
[sqlobj openDb];
NSString *query = [NSString stringWithFormat:@"SELECT *FROM MASTER_PRJ_DETAILS WHERE M_ID = \'%@\'", [masterProjIDArray objectAtIndex:i]];
NSLog(@"SQL query:%@", query);
[sqlobj readDb:query];
while ([sqlobj hasNextRow])
{
NSString *mProjIssuesID = [sqlobj getColumn:1 type:@"text"];
[masterProjIssueIDArray addObject:mProjIssuesID];
}
NSLog(@"issueCount:%@", masterProjIssueIDArray);
[sqlobj closeDb];
}
[sqlobj release];
请给我一些关于显示个人数量M_ID问题的建议。
答案 0 :(得分:0)
NSLog(@“issueCount:%d”,[masterProjIssueIDArray count]);
答案 1 :(得分:0)
有两种方法可以计算
使用数组计数
[masterProjIssueIDArray count]
或在数据库中计数
SELECT count(*) FROM MASTER_PRJ_DETAILS
希望它可以帮到你
答案 2 :(得分:0)
MySQLite *sqlobj = [[MySQLite alloc] initWithSQLFile:@"myDb"];
[sqlobj openDb];
NSString *query = [NSString stringWithFormat:@"SELECT *FROM MASTER_PRJ_DETAILS WHERE M_ID = '%@'",M1];
NSLog(@"SQL query:%@", query);
NSMutableArray *arrydata= [sqlobj readDb:query];
//You got 3 records...
for (int i = 0; i < [arrydata count]; i++)
{
NSMUtableDisctionry *dist=[arrydata objectAtIndex:i];
NSString *strIsuue=[dist objectforkey:@"M_ISSUE"];
[masterProjIssueIDArray addObject:strIsuue];
NSLog(@"issueCount:%@", masterProjIssueIDArray);
}
[sqlobj closeDb];
[sqlobj release];
我希望它的工作......