Question

弹出web流子sub子流状态，打开相同的jsp 我的代码是：

点击按钮中的jsp：

$（ “＃formid”）得到（0）.setAttribute（ '动作'， '搜索-comune.htm'）; $（ “＃formid”）提交（）;

控制器：

  @RequestMapping("/aut/nuovo-operatore-rer")
            public ModelMap start() {

            OperatoreRerVO opVO = new OperatoreRerVO();
            ModelMap model = new ModelMap();
            model.addAttribute("OperatoriRer",opVO);
            return model;
            }


         @RequestMapping(value = "/aut/search-comune", method = RequestMethod.POST)
            public ModelMap searchcomune(@ModelAttribute("OperatoriRer") OperatoreRerVO opVO) {
            List<Comuni> comuniList = new ArrayList <Comuni>() ;
            Comuni comune = new Comuni();
            String descrizione  = "%"+opVO.getComune().getDescrizione().toUpperCase()+"%";
            comuniList = comuniDao.selectByName(descrizione);
            ModelMap model = new ModelMap();
            model.addAttribute("comuniList",comuniList);
            model.addAttribute("OperatoriRer",opVO);
            return model;
            }

flow xml：

<view-state id="nuovo-operatore-rer" view="aut/nuovo-operatore-rer">
</view-state>
<view-state id="search-comune" view="aut/nuovo-operatore-rer" />

servlet

<webflow:flow-location id="aut/nuovo-operatore-rer" path="/WEB-INF/flows/aut/nuovo-operatore-rer.xml" />
        <webflow:flow-location id="aut/search-comune" path="/WEB-INF/flows/aut/nuovo-operatore-rer.xml" />

jsp名称：nuovo-operatore-rer.jsp

不起作用。

Answer 1

如果您希望能够使用不同的ID来调用它们，则需要将流分开为2 （顺便说一句，你的流的id不必与你的视图状态的id相同）

flow1（aut / nuovo-operatore-rer.xml）：

<view-state id="view1" view="aut/nuovo-operatore-rer">
</view-state>

flow2（aut / search-comune.xml）：

<view-state id="view2" view="aut/nuovo-operatore-rer">
</view-state>

<webflow:flow-location id="aut/nuovo-operatore-rer" path="/WEB-INF/flows/aut/nuovo-operatore-rer.xml" />
<webflow:flow-location id="aut/search-comune" path="/WEB-INF/flows/aut/search-comune.xml" />

spring web flow sub子流状态，打开相同的jsp

1 个答案: