Question

我写了下面的查询

SELECT DEPT_ID, COUNT(*) AS stud_count FROM TBL_STUDENT_DEPARTMENT_593932       
        GROUP BY DEPT_ID ORDER BY stud_count DESC

输出：

DEPT_ID     STUD_COUNT
-------     ----------
Dep02                5
Dep03                4
Dep01                3

我想选择第二大的stud_count，即4。所以我使用 rownum 如下

SELECT stud_count FROM
(
    SELECT DEPT_ID, COUNT(*) AS stud_count FROM TBL_STUDENT_DEPARTMENT_593932       
        GROUP BY DEPT_ID ORDER BY stud_count DESC
)
WHERE ROWNUM = 2;

但是它不返回任何行，只是空表。我怎么能这样做？

Answer 1

ROWNUM以特殊方式运行，这就是您需要使用嵌套查询的原因。首先，您将所有数据分组并汇总。在外部查询中，您可以分配行号。在最外面的查询中，您只选择第二行。

SELECT *
FROM
   (
   SELECT dept_id
   ,      stud_count
   ,      rownum as stud_num
   FROM
      (
      SELECT DEPT_ID
      ,      COUNT(*) AS stud_count 
      FROM   TBL_STUDENT_DEPARTMENT_593932       
      GROUP BY DEPT_ID 
      ORDER BY stud_count DESC
      )
   )
WHERE stud_num = 2;

如果您熟悉分析功能，则可以改为使用此语句：

SELECT *
FROM
   (
   SELECT DEPT_ID
   ,      COUNT(*) AS stud_count
   ,      ROW_NUMBER() over (order by COUNT(*) desc) stud_num
   FROM   TBL_STUDENT_DEPARTMENT_593932       
   GROUP BY DEPT_ID
)
WHERE stud_num = 2;

Answer 2

请检查：

SELECT * FROM
(
    SELECT DEPT_ID, COUNT(*) AS stud_count, ROW_NUMBER() over (order by COUNT(*) desc) ROW_NUM
    FROM TBL_STUDENT_DEPARTMENT_593932       
        GROUP BY DEPT_ID
)
WHERE ROW_NUM = 2;

Answer 3

你必须嵌套另一个级别

select dept_id, stud_count
  from (select rownum r, dept_id, stud_count
          from (select dept_id, count(*) as stud_count 
                  from TBL_STUDENT_DEPARTMENT_593932
                 GROUP BY DEPT_ID 
                 order by stud_count desc)
         where rownum <= 2
       )
 where r = 2;

但使用rownum意味着如果两个或多个记录具有第二个计数，则只能获得一行。所以使用你所需要的第二个最高计数的密集的你想要的所有行。

   select dept_id, stud_count
     from (select dept_id, count(*) as stud_count,
                  dense_rank() over (order by count(*) desc) rnk
             from TBL_STUDENT_DEPARTMENT_593932
             GROUP BY DEPT_ID 
             order by stud_count desc)
     where rnk = 2;

例如：

SQL> select dept_id, count(*) stud_count from tbl_student_department_593932 group by dept_id;

DEPT_ STUD_COUNT
----- ----------
Dep03          4 <-- 
Dep01          3
Dep05          4 <-- 
Dep02          6

SQL> select dept_id, stud_count
  2    from (select rownum r, dept_id, stud_count
  3             from (select dept_id, count(*) as stud_count
  4                      from tbl_student_department_593932
  5                     group by dept_id
  6                     order by stud_count desc)
  7            where rownum <= 2)
  8   where r = 2;

DEPT_ STUD_COUNT
----- ----------
Dep03          4

VS

SQL> select dept_id, stud_count
  2    from (select dept_id, count(*) as stud_count,
  3                  dense_rank() over(order by count(*) desc) rnk
  4             from tbl_student_department_593932
  5            group by dept_id
  6            order by stud_count desc)
  7   where rnk = 2;

DEPT_ STUD_COUNT
----- ----------
Dep03          4
Dep05          4

Answer 4

SELECT TOP DEPT_ID, COUNT(*) AS stud_count 
FROM TBL_STUDENT_DEPARTMENT_593932 tb1
INNER JOIN tbl_student_department_593932 tb2
ON tb1.dept_id = tb2.dept_id
where tb1.count < tb2.count

访问结果中的第二行

4 个答案: