强制GraphViz强制子图之间对齐

Question

我使用GraphViz和以下点文件：

digraph "Fast-forward"
{
    rankdir=LR;
    subgraph master
    {
        "5c071a6b2c" -> "968bda3251";
    }
    subgraph branch
    {
        "35ee8ce6b6" [color="blue"] [style="filled"];
        "968bda3251" -> "9754d40473" [weight=0];
        "9754d40473" -> "9e59700d33" -> "35ee8ce6b6";
    }
    subgraph c1
    {
        rankdir=LR;
        rank="same";
        "remote/master/HEAD" [shape=box];
        "remote/master/HEAD" -> "35ee8ce6b6" [weight=0];
        oldmh [label="master/HEAD"] [shape=box] [color="red"] [style="filled"];
        newmh [label="master/HEAD"] [shape=box] [color="blue"] [style="filled"];
        oldmh -> "968bda3251" [weight=0];
        newmh -> "35ee8ce6b6" [weight=0];
    }
}

它给我这样的东西：

但我想要这样的东西：

                                                     white
                                                        |
                                                       \/
                     "9754d40473" -> "9e59700d33" -> "35ee8ce6b6";
                     /                                  /\

     

5c071a6b2c - ＆gt; 968bda3251

             /\                                         |
              |
            red                                       blue

我该怎么做？

为了你的帮助， 先谢谢。

Answer 1

我倾向于首先定义所有具有特殊需求的节点（如同一级别或具有特殊形状/颜色），然后定义链接。这样，您可以确保rank=same个节点已正确分组，并按正确的顺序定义。

如果没有weight=0，则所有侧链接都位于顶部。将weight=0添加到底部的所需内容。

digraph "Fast-forward"
{
    rankdir=LR;
    subgraph c1 {
        rank="same";
        "968bda3251";
        oldmh [label="master/HEAD"] [shape=box] [color="red"] [style="filled"];
    }
    subgraph c2
    {
        rank="same";
        "remote/master/HEAD" [shape=box];
        "35ee8ce6b6" [color="blue"] [style="filled"];
        newmh [label="master/HEAD"] [shape=box] [color="blue"] [style="filled"];
    }
    "5c071a6b2c" -> "968bda3251" -> "9754d40473" -> "9e59700d33" -> "35ee8ce6b6";
    oldmh -> "968bda3251" [weight=0];
    "remote/master/HEAD" -> "35ee8ce6b6";
    newmh -> "35ee8ce6b6" [weight=0];
}

如果你真的想要在96到97之间慢跑，你可以这样做：

digraph "Fast-forward"
{
    rankdir=LR;
    subgraph c1 {
        rank=same;
        "968bda3251";
        oldmh [label="master/HEAD"] [shape=box] [color="red"] [style="filled"];
    }
    subgraph c1p5 {
        rank=same;
        "9754d40473";
        inviso [style="invis"];
    }
    subgraph c2
    {
        rank="same";
        "remote/master/HEAD" [shape=box];
        "35ee8ce6b6" [color="blue"] [style="filled"];
        newmh [label="master/HEAD"] [shape=box] [color="blue"] [style="filled"];
    }
    "5c071a6b2c" -> "968bda3251";
    "968bda3251" -> "9754d40473" [weight=0];
    "9754d40473" -> "9e59700d33" -> "35ee8ce6b6";
    oldmh -> "968bda3251" [weight=0];
    "remote/master/HEAD" -> "35ee8ce6b6";
    newmh -> "35ee8ce6b6" [weight=0];
    "968bda3251" -> inviso [style="invis"];
    "9754d40473" -> inviso [style="invis"];
}

Answer 2

rank="same"会影响子图的所有节点，因此您必须将标记子图拆分为两部分：

digraph "Fast-forward"
{
    rankdir=LR;
    subgraph master
    {
        "5c071a6b2c" -> "968bda3251";
    }
    subgraph branch
    {
        "968bda3251" -> "9754d40473" [weight=0];
        "9754d40473" -> "9e59700d33" -> "35ee8ce6b6";
        "35ee8ce6b6" [color="blue"] [style="filled"];
    }
    subgraph c1
    {
        rank="same";
        "remote/master/HEAD" [shape=box];
        "remote/master/HEAD" -> "35ee8ce6b6" [weight=0];
        newmh [label="master/HEAD"] [shape=box] [color="blue"] [style="filled"];
        newmh -> "35ee8ce6b6" [weight=0];
    }
    subgraph c2
    {
        rank="same";
        oldmh [label="master/HEAD"] [shape=box] [color="red"] [style="filled"];
        oldmh -> "968bda3251" [weight=0];
    }
}

这会给你：