我有一个计时器功能,我想清除超时或重置功能,因为每次执行它时,都会创建一个新的超时,所以我收到了几个计数。 我的想法是每次执行函数时重置计数。我只需要1个计时器实例并获得正确的计数。如果if多次执行我要重启的函数为0。
这是我的代码:
var timeouts = new Array();
var timer = null;
io.sockets.on('connection', function (client)
{
client.on("start", function (){
console.log('Someone has pressed Start button',new Date().getTime());
//try to kill all timeouts
for (var timeout in timeouts) {
clearTimeout(timeout);
};
if(this.timer == null) {
this.timer = new timer(1000, function (data) {
io.sockets.emit('timeupdate', data);
})
}else {
this.timer = null;
});
});
function timer(delay, callback)
{
// self-reference
var self = this;
if (!(this instanceof timer)) {
return new timer();
}
// attributes
var counter = 0;
var start = new Date().getTime();
/**
* Delayed running of the callback.
*/
function delayed()
{
console.log(counter);
callback(counter);
counter ++;
var diff = (new Date().getTime() - start) - counter * delay;
var timeOut = setTimeout(delayed, delay - diff);
timeouts.push(timeOut);
}
// start timer
delayed();
var timeout = setTimeout(delayed, delay);
timeouts.push(timeout);
}
提前谢谢。
答案 0 :(得分:2)
使用clearTimeout()
是正确的方法。问题是你的for
- 循环。这可能看起来像一个经典的foreach
- 循环,但事实并非如此。你必须这样做:
for (var i=0; i< timeouts.length; i++) {
clearTimeout(timeouts[i]);
}
或者,我也不喜欢这个:
for (var i in timeouts) {
clearTimeout(timeouts[i]); // note how the array is indexed using var i
}
这是一个常见的JavaScript陷阱 - for (x in y)
- 循环实际上迭代数组的索引,而不是值。它还可以迭代对象的属性。试试吧:
var a = [3, 2, 5, 8];
for (var i in a) {
console.log(i);
console.log(a[i]);
}
var o = { test: 'hello', number: 1234 };
for (var x in o)
console.log(x);