Question

我有两张桌子，我应该在数量，数量和平衡数量的库存物品中显示我写下我的查询如下：

SELECT I.Date as Date, 
P.ResourceName as ItemName,
P.ResourceRate as Rate,
i.TotalInQty as InwardsQuantity,
s.TotalOutQty as OutwardsQuantity,
i.TotalInQty-S.TotalOutQty as Balance,
O.UnitSymbol As ItemUnit
FROM UnitMaster O
INNER JOIN Resource_Master P
 ON O.UnitCode = P.Unitcode
LEFT JOIN
(
  select sum(i.Qty) TotalInQty, Nameofitem
  from Inwards_Master I
  group by Nameofitem
) I
ON I.Nameofitem= P.ResourceName
LEFT JOIN
(
  select sum(s.qty) TotalOutQty, Nameofitem
  from Outwards_Master S 
  group by s.Nameofitem
) S
ON I.Date=S.Date 
AND I.Nameofitem =S.Nameofitem
WHERE P.TenderCode=1

以上查询给出了如下错误：

Msg 8120，Level 16，State 1，Line 14 Column'Inwards_Master.Date'是在选择列表中无效，因为它不包含在任何一个中聚合函数或GROUP BY子句。

任何1请帮帮我

Answer 1

这是因为您没有从表格引用Date而不是i中选择s列，您应该将其包含在具有汇总功能MIN的选择列表中，或者MAX，或者将其包含在GROUP BY子句中，如下所示：

SELECT 
  I.Date as Date, 
  P.ResourceName as ItemName,
  P.ResourceRate as Rate,
  i.TotalInQty as InwardsQuantity,
  s.TotalOutQty as OutwardsQuantity,
  i.TotalInQty - S.TotalOutQty as Balance,
  O.UnitSymbol As ItemUnit
FROM UnitMaster O
INNER JOIN Resource_Master P ON O.UnitCode = P.Unitcode
LEFT JOIN
(
  select 
    sum(i.Qty) TotalInQty, 
    "Date",
    Nameofitem
  from Inwards_Master I
  group by Nameofitem, "Date"
) I
ON I.Nameofitem = P.ResourceName
LEFT JOIN
(
  select 
    sum(s.qty) TotalOutQty, 
    "Date",
    Nameofitem
  from Outwards_Master S 
  group by s.Nameofitem, "Date"
) S  ON I.Date       = S.Date 
    AND I.Nameofitem = S.Nameofitem
WHERE P.TenderCode = 1;

或者：如果您不需要GROUP BY日期，那么您希望为每个分组Nameofitem获取哪个日期？

在这种情况下，您必须使用聚合函数。例如MAX(Date)以获取最新日期：

...
LEFT JOIN
(
  select 
    sum(i.Qty) TotalInQty, 
    MAX("Date") LatestDate,
    Nameofitem
  from Inwards_Master I
  group by Nameofitem
) I

s也一样。

Answer 2

正如它所说的那样 - 所以请尝试将I.Date和S.Date包含在聚合中：

SELECT I.Date as Date, 
P.ResourceName as ItemName,
P.ResourceRate as Rate,
i.TotalInQty as InwardsQuantity,
s.TotalOutQty as OutwardsQuantity,
i.TotalInQty-S.TotalOutQty as Balance,
O.UnitSymbol As ItemUnit
FROM UnitMaster O
INNER JOIN Resource_Master P
 ON O.UnitCode = P.Unitcode
LEFT JOIN
(
  select COALESCE(sum(i.Qty), 0) AS TotalInQty, Nameofitem, Min(I.Date) AS Date
  from Inwards_Master I
  group by Nameofitem
) I
ON I.Nameofitem= P.ResourceName
LEFT JOIN
(
  select COALESCE(sum(s.qty), 0) AS TotalOutQty, Nameofitem, Min(S.Date) AS Date
  from Outwards_Master S 
  group by s.Nameofitem
) S
ON I.Date=S.Date 
AND I.Nameofitem =S.Nameofitem
WHERE P.TenderCode=1

在SQL SERVER中平衡库存

2 个答案: