Question

String haiku1 = "As the wind does blow\nAcross the trees, I see the\nBuds blooming in May."; 
String haiku2 = "I walk across sand\nAnd find myself blistering\nIn the hot, hot heat."; 
String haiku3 = "Falling to the ground,\nI watch a leaf settle down\nIn a bed of brown.";  
String haiku4 = "It’s cold and I wait\nFor someone to shelter me\nAnd take me from here.";

我需要在上面列出的四个中打印一个随机字符串。我怎么能这样做？我知道我必须随机使用。谢谢你的帮助

Answer 1

最好将字符串放在数组中。

String haiku[] = new String[4];
haiku[0] = "/*your string*/";
haiku[1] = "/*your string*/";
haiku[2] = "/*your string*/";
haiku[3] = "/*your string*/";

然后从0-3生成随机数以访问数组的索引。

Random randomizer = new Random();         //import java.util.Random;
int index = randomizer.nextInt(4);
System.out.println("Generated random string: " + haiku[index]);

Answer 2

喜欢这个 -

    ...
    int nextInt = new Random().nextInt(4);
    switch (nextInt) {
    case 1:
        System.out.println(haiku1);
        break;
    case 2:
        System.out.println(haiku2);
        break;
    case 3:
        System.out.println(haiku3);
        break;
    case 4:
        System.out.println(haiku4);
        break;

    }

Answer 3

创建上述字符串的数组，并使用java.util.Random类为数组索引生成随机数。

Answer 4

您应该将此字符串放在数组中。

进一步参考请在下面链接chekc。 Retrieving a random item from ArrayList

Answer 5

生成一个随机数，然后访问存储在数组中特定位置的值：

  Random r = new Random();
  int index = r.nextInt(4);

Answer 6

我会这样做：

String[] myArray = {haiku1,haiku2,haiku3,haiku4};
Random rand = new Random();
int randomnum = rand.nextint(4);
System.out.println(myArray[randomnum]);

Answer 7

   String haiku1 = ("As the wind does blow\nAcross the trees, I see the\nBuds blooming in May.");
    String haiku2 = ("I walk across sand\nAnd find myself blistering\nIn the hot, hot heat.");
    String haiku3 = ("Falling to the ground,\nI watch a leaf settle down\nIn a bed of brown.");
    String haiku4 = ("It’s cold and I wait\nFor someone to shelter me\nAnd take me from here.");

    String[] array={haiku1,haiku2,haiku3,haiku4};

    Random rndm=new Random();

    System.out.println( "Generated Random String: "+array[rndm.nextInt((array.length-1) - 0 + 1) + 0]);

如何从4打印1个随机字符串？

7 个答案: