当用户将鼠标悬停并单击时,我正在尝试更改div的背景图像。我坚持将图像限制为仅更改为用户悬停/单击的元素。在此示例中,当悬停/单击一个div时,所有按钮都将更改。这是我正在尝试复制已经在jQuery中工作的东西。我猜它可以使用“这个”,但到目前为止我尝试过的所有方法都会导致错误。
任何人告诉我为什么在Firefox中页面加载时警报发生而不是IE或Chrome
的奖励积分的JavaScript
var buttons = document.getElementsByTagName('div');
var i;
function iconDown(e) {
for (i=0; i<buttons.length; i++) {
buttons[i].style.backgroundPosition = '0px -61px';
}
}
function iconUp(e) {
for (i=0; i<buttons.length; i++) {
buttons[i].style.backgroundPosition = '0px -122px';
}
}
function iconOver(e) {
for (i=0; i<buttons.length; i++) {
buttons[i].style.backgroundPosition = '0px -122px';
}
}
function iconOut(e) {
for (i=0; i<buttons.length; i++) {
buttons[i].style.backgroundPosition = '0px 0px';
}
}
function processAction() {
alert("Working!");
}
function Init () {
for (i=0; i<buttons.length; i++) {
if (document.addEventListener) { // all browsers except IE before version 9
buttons[i].addEventListener ("mousedown", iconDown, false);
buttons[i].addEventListener ("mouseup", iconUp, false);
buttons[i].addEventListener ("mouseover", iconOver, false);
buttons[i].addEventListener ("mouseout", iconOut, false);
buttons[i].addEventListener("click", processAction, false);
}
else { // IE before version 9
buttons[i].attachEvent ("onmousedown", iconDown);
buttons[i].attachEvent ("onmouseup", iconUp);
buttons[i].attachEvent ("onmouseover", iconOver);
buttons[i].attachEvent ("onmouseout", iconOut);
buttons[i].attachEvent("onclick", processAction);
}
}
}
Init();
CSS
.btn {width:100px; height:61px; float:left;}
#BackImg {background: url('images/Back.gif') no-repeat 0px 0px;}
#NextImg {background: url('images/Next.gif') no-repeat 0px 0px;}
HTML
<DIV class="btn" ID="BackImg"></DIV>
<DIV class="btn" ID="NextImg"></DIV>
答案 0 :(得分:1)
你不需要任何javascript。只需使用css。
.specialClassyClass{
/*default background position*/
}
.specialClassyClass:hover{
/*hover state background position*/
}
.specialClassyClass:active{
/*mouse down background position*/
}
点击内容:
var whatever = function(el, ev, handler){
el.attachEvent?
el.attachEvent(ev, handler):
el.addEventListener(ev, handler, false);
}
whatever(button[i], 'click', processAction);
答案 1 :(得分:0)
您可以使用:
function processAction(e) {
var active = document.querySelector('.active'); // get currently active button
if(active != undefined)
active.className = "btn"; // remove active class
e.target.className = 'btn active' // add active class to clicked element
}
然后你的css就像:
.btn {width:100px; height:61px; float:left;background: orange;}
.active {background: red;}