Question

以下SQL语句：

SELECT f.id, 
       f.front, 
       f.back, 
       h.statusChangedIdCode, 
       h.whenCreated,
       h.historyIdCode 
FROM dpod_site_flashcards AS f 
   JOIN dpod_site_historyItems AS h ON f.id = h.itemId 
WHERE f.id = 216 
  AND historyIdCode = 'statusChanged' 
ORDER BY h.whenCreated

给我以下输出。 如何更改它以便它只返回一行具有最新statusChangedIdCode？

Answer 1

SELECT f.id, 
       f.front, 
       f.back, 
       h.statusChangedIdCode, 
       h.whenCreated,
       h.historyIdCode 
FROM dpod_site_flashcards AS f 
   JOIN dpod_site_historyItems AS h ON f.id = h.itemId 
WHERE f.id = 216 
  AND h.historyIdCode = 'statusChanged' 
  AND h.whenCreated = (select max(whenCreated)
                       from dpod_site_historyItems h2
                       where h2.itemId = h.itemId
                         and h2.historyIdCode = 'statusChanged')
ORDER BY h.whenCreated

或者如果您有支持窗口函数的现代DBMS：

SELECT f.id, 
       f.front, 
       f.back, 
       h.statusChangedIdCode, 
       h.whenCreated,
       h.historyIdCode 
FROM dpod_site_flashcards AS f 
   JOIN (
     select itemid, 
            historyIdCode,
            whenCreated,
            statusChangedIdCode,
            row_number() over (partition by itemid order by whenCreated desc) as rn 
     from dpod_site_historyItems 
     where historyIdCode = 'statusChanged' 
   ) h ON f.id = h.itemId AND h.rn = 1
WHERE f.id = 216 
ORDER BY h.whenCreated

当您选择LIMIT解决方案不会执行的多个dpod_site_flashcards.id的行时，这两种情况都会起作用。

Answer 2

试过这个？

SELECT f.id, f.front, f.back, h.statusChangedIdCode, MAX(h.whenCreated), h.historyIdCode 
FROM dpod_site_flashcards AS f 
JOIN dpod_site_historyItems AS h ON f.id=h.itemId 
WHERE f.id = 216 AND historyIdCode='statusChanged' 
GROUP BY f.id, f.front, f.back, h.statusChangedIdCode, h.historyIdCode

-EDIT

哎呀，谢谢@Gordon，没有仔细阅读要求。这是一些应该完成工作的SQLFiddle。

这是正确代码的代码片段 - 在WHERE子句中包含它：

h.whenCreated = (select max(whenCreated)
   from dpod_site_historyItems h2
   where h2.itemId = h.itemId)

Answer 3

如果您使用MySQL，请将结尾更改为：ORDER BY h.whenCreated DESC LIMIT 1

Answer 4

这是基于@ itchy的答案。最佳答案取决于数据库。

有些数据库支持limit，所以答案是：

SELECT f.id, 
       f.front, 
       f.back, 
       h.statusChangedIdCode, 
       h.whenCreated,
       h.historyIdCode 
FROM dpod_site_flashcards AS f 
   JOIN dpod_site_historyItems AS h ON f.id = h.itemId 
WHERE f.id = 216 
  AND historyIdCode = 'statusChanged' 
ORDER BY h.whenCreated
limit 1

SQL Server和Sybase支持top，导致：

SELECT top 1 f.id, 
       f.front, 
       f.back, 
       h.statusChangedIdCode, 
       h.whenCreated,
       h.historyIdCode 
FROM dpod_site_flashcards AS f 
   JOIN dpod_site_historyItems AS h ON f.id = h.itemId 
WHERE f.id = 216 
  AND historyIdCode = 'statusChanged' 
ORDER BY h.whenCreated

Oracle使用rownum，但您需要一个子查询：

select * from (SELECT f.id, 
       f.front, 
       f.back, 
       h.statusChangedIdCode, 
       h.whenCreated,
       h.historyIdCode 
FROM dpod_site_flashcards AS f 
   JOIN dpod_site_historyItems AS h ON f.id = h.itemId 
WHERE f.id = 216 
  AND historyIdCode = 'statusChanged' 
ORDER BY h.whenCreated
) t
where rownum = 1

DB2使用fetch_first：

SELECT f.id, 
       f.front, 
       f.back, 
       h.statusChangedIdCode, 
       h.whenCreated,
       h.historyIdCode 
FROM dpod_site_flashcards AS f 
   JOIN dpod_site_historyItems AS h ON f.id = h.itemId 
WHERE f.id = 216 
  AND historyIdCode = 'statusChanged' 
ORDER BY h.whenCreated
fetch first 1 row only

如何使SQL JOIN只返回最近状态代码的一行？

4 个答案: