Question

我很难找到描述我问题的词语，因此谷歌没有提出任何结果。对不起，这可能是一个非常简单的问题。

基本上我想要有两行，这两行都是由语句之间的个别创建的。我尝试过像在Select中那样使用“AS”语句，但这只是给我一个语法错误。

这是我的代码：

Select      WEEK_ID,
            SUM (CUR_CHARGE_UNITS) as "Pro Units"
From        DW******.SLS****
Where       (WEEK_ID Between '201201' And '201252') --Use 'as' statement here?
            Or (WEEK_ID Between '201101' And '201152')
Group By    WEEK_ID

基本上我正在试图弄清楚如何制作

WEEK_ID Between '201201' And '201252'

崩溃成一行标题为“2012”。就像我说的，我所尝试过的只是

(WEEK_ID Between '201201' And '201252) As "2012"

有什么想法？有人想指点我的任何教程吗？任何因为不知道基本问题答案的侮辱？

Answer 1

尝试获取前4个字符并将其分组：

Select      LEFT(WEEK_ID,4) AS Year,
            SUM (CUR_CHARGE_UNITS) as "Pro Units"
From        DW******.SLS****
Where       (WEEK_ID Between '201201' And '201252') --Use 'as' statement here?
            Or (WEEK_ID Between '201101' And '201152')
Group By    LEFT(WEEK_ID,4)

好处是LEFT是ANSI所以应该适用于所有rdbms

Answer 2

听起来你需要一个案例陈述

http://publib.boulder.ibm.com/infocenter/dzichelp/v2r2/index.jsp?topic=%2Fcom.ibm.db2.doc.sqlref%2Fpsmcse.htm

select
    case when week_id between '201201' and '201252'
              then '2012'
          when week_id between '201101' and '201152'
              then '2011'
     end as 'year'
        SUM (CUR_CHARGE_UNITS) as "Pro Units"
From        DW******.SLS****
Where       (WEEK_ID Between '201201' And '201252')
        Or (WEEK_ID Between '201101' And '201152')
Group By 
     case when week_id between '201201' and '201252'
              then '2012'
          when week_id between '201101' and '201152'
              then '2011'
     end

Answer 3

就“任何想法”而言，我建议您只研究GROUP BY子句和SQL聚合的概念。

如果您想汇总一年中的所有周，那么不想要按WEEK_ID选择或分组（您希望按年分组）

将between语句用作组

3 个答案: