同步线程进行图像处理Delphi

时间:2013-01-09 15:32:53

标签: multithreading delphi synchronization delphi-xe3 tthread

我必须以主要形式处理一个图像,但是对于inc速度,处理速度很低我使用线程...

我的线程代码:

type
  TPaintThread = class(TThread)
    Source,Mask :TBitmap ;
    image : TImage;
    public
       procedure SetAll(src,msk:TBitmap;img:TImage);
    private
     procedure  DoWritePix;
    var
       mBit : TBitmap ;

    protected
      procedure Execute; override;
  end;

implementation

procedure TPaintThread.SetAll(src: TBitmap; msk: TBitmap; img: TImage);
begin
      Source := src ;
      mask := msk ;
      img := img ;
      mBit := TBitmap.Create ;
end;

procedure TPaintThread.DoWritePix;
begin
  image.Picture.Bitmap := mBit ;
end;

procedure TPaintThread.Execute;
var
    i: Integer;
    j: Integer;
begin
  mBit.Width := Source.Width ;
  mBit.Height := Source.Height ;
  for i := 1 to Source.Width do
    for j := 1 to Source.Width do
    begin
      // my processing event
    end;
    // result := mBit ;
    // write on form image 
    Synchronize(DoWritePix);
end;

我在timer上使用它:

procedure TForm1.tmr1Timer(Sender: TObject);
var
    pThread  : TPaintThread ;
begin
  pThread := TPaintThread.Create(True) ;
  pThread.SetAll(MyBmp,mask,img1);
  pThread.Resume ;
  pThread.FreeOnTerminate := True ;
end;

但我在运行时DoWritePix出错:

First chance exception at $005A81DE. Exception class $C0000005 with message 'access violation at 0x005a81de: read of address 0x000001b8'. Process myexe.exe (6032)
First chance exception at $754E9617. Exception class EAccessViolation with message 'Access violation at address 005A81DE in module 'myexe.exe'. Read of address 000001B8'. Process myexe.exe (6032) 

我的问题:对于主要表单中的编辑图像,这种方式是否正确?如果不是正确的方式访问和写在线程上?如果是,我怎么解决问题?

1 个答案:

答案 0 :(得分:8)

此代码错误:

procedure TPaintThread.SetAll(src: TBitmap; msk: TBitmap; img: TImage);
begin
  Source := src ;
  mask := msk ;
  img := img ; // OOPS!
  mBit := TBitmap.Create ;
end;

当你写img := img;时你什么都不做 - 这是一个无操作。你打算写:

image := img;

这就是imagenil DoWritePix解释访问冲突的原因。

遇到运行时错误时不要无助。在调试器下运行代码,让调试器告诉你哪个变量没有初始化。