我正在开发一个Android应用程序。该应用程序有一个包含大量图像的视图。我有一个错误，我会尝试提供尽可能多的信息，希望有人能给我一些建议。
该应用程序在所有本地测试中都运行良好。但是，我收到了很多来自用户的崩溃：java.lang.OutOfMemoryError: bitmap size exceeds VM budget
这是堆栈跟踪
0 java.lang.OutOfMemoryError: bitmap size exceeds VM budget
1 at android.graphics.Bitmap.nativeCreate(Native Method)
2 at android.graphics.Bitmap.createBitmap(Bitmap.java:507)
3 at android.graphics.Bitmap.createBitmap(Bitmap.java:474)
4 at android.graphics.Bitmap.createScaledBitmap(Bitmap.java:379)
5 at android.graphics.BitmapFactory.finishDecode(BitmapFactory.java:498)
6 at android.graphics.BitmapFactory.decodeStream(BitmapFactory.java:473)
7 at android.graphics.BitmapFactory.decodeResourceStream(BitmapFactory.java:336)
8 at android.graphics.BitmapFactory.decodeResource(BitmapFactory.java:359)
9 at android.graphics.BitmapFactory.decodeResource(BitmapFactory.java:385)
我最大的问题是，即使在旧设备上，我也无法在本地重现此问题。
我已经实施了很多东西来尝试解决这个问题：
onDestroy()方法inSampleSize。计算正确inSampleSize的代码
public static int calculateInSampleSize(BitmapFactory.Options options, int reqWidth, int reqHeight)
{
// Raw height and width of image
final int height = options.outHeight;
final int width = options.outWidth;
int inSampleSize = 1;
if(height > reqHeight || width > reqWidth)
{
if(width > height)
{
inSampleSize = Math.round((float) height / (float) reqHeight);
}
else
{
inSampleSize = Math.round((float) width / (float) reqWidth);
}
}
return inSampleSize;
}
获取位图的代码
// decodes image and scales it to reduce memory consumption
private static Bitmap decodeFile(File file, int newWidth, int newHeight)
{// target size
try
{
Bitmap bmp = MediaStore.Images.Media.getBitmap(getContext().getContentResolver(), Uri.fromFile(file));
if(bmp == null)
{
// avoid concurrence
// Decode image size
BitmapFactory.Options option = new BitmapFactory.Options();
// option = getBitmapOutput(file);
option.inDensity = res.getDisplayMetrics().densityDpi < DisplayMetrics.DENSITY_HIGH ? 120 : 240;
option.inTargetDensity = res.getDisplayMetrics().densityDpi;
if(newHeight > 0 && newWidth > 0)
option.inSampleSize = calculateInSampleSize(option, newWidth, newWidth);
option.inJustDecodeBounds = false;
byte[] decodeBuffer = new byte[12 * 1024];
option.inTempStorage = decodeBuffer;
option.inPurgeable = true;
option.inInputShareable = true;
option.inScaled = true;
bmp = BitmapFactory.decodeStream(new FileInputStream(file), null, option);
if(bmp == null)
{
return null;
}
}
else
{
int inDensity = res.getDisplayMetrics().densityDpi < DisplayMetrics.DENSITY_HIGH ? 120 : 240;
int inTargetDensity = res.getDisplayMetrics().densityDpi;
if(inDensity != inTargetDensity)
{
int newBmpWidth = (bmp.getWidth() * inTargetDensity) / inDensity;
int newBmpHeight = (bmp.getHeight() * inTargetDensity) / inDensity;
bmp = Bitmap.createScaledBitmap(bmp, newBmpWidth, newBmpHeight, true);
}
}
return bmp;
}
catch(Exception e)
{
Log.e("Error calling Application.decodeFile Method params: " + Arrays.toString(new Object[]{file }), e);
}
return null;
}
根据旧设备的堆大小计算图片大小的代码
private void calculateImagesSize()
{
// only for android older than HoneyComb that does not support large heap
if(Build.VERSION.SDK_INT < Constants.HONEYCOMB)
{
long maxHeapSize = Runtime.getRuntime().maxMemory();
long maxImageHeap = maxHeapSize - 10485760;
if(Application.getResource().getDisplayMetrics().densityDpi >= DisplayMetrics.DENSITY_XHIGH)
{
maxImageHeap -= 12 * 1048576;
}
if(maxImageHeap < (30 * 1048576))
{
int screenHeight = Math.min(Application.getResource().getDisplayMetrics().heightPixels, Application.getResource()
.getDisplayMetrics().widthPixels);
long maxImageSize = maxImageHeap / 100;
long maxPixels = maxImageSize / 4;
long maxHeight = (long) Math.sqrt(maxPixels / 1.5);
if(maxHeight < screenHeight)
{
drawableHeight = (int) maxHeight;
drawableWidth = (int) (drawableHeight * 1.5);
}
}
}
}
我认为问题出在Heap上，有时os可能不允许应用程序使用maxheapsize。另外我最大的问题是我无法重现这个问题，所以当我尝试修复时，我必须等一下，看看用户是否仍然收到错误。
我还可以尝试避免内存不足问题？任何建议将不胜感激。非常感谢
答案 0 :(得分：8)
只需使用此功能进行解码...这是您错误的完美解决方案。因为我也得到了相同的错误，我得到了这个解决方案..
public static Bitmap decodeFile(File f,int WIDTH,int HIGHT){
try {
//Decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
BitmapFactory.decodeStream(new FileInputStream(f),null,o);
//The new size we want to scale to
final int REQUIRED_WIDTH=WIDTH;
final int REQUIRED_HIGHT=HIGHT;
//Find the correct scale value. It should be the power of 2.
int scale=1;
while(o.outWidth/scale/2>=REQUIRED_WIDTH && o.outHeight/scale/2>=REQUIRED_HIGHT)
scale*=2;
//Decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
o2.inSampleSize=scale;
return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
} catch (FileNotFoundException e) {}
return null;
}
答案 1 :(得分：5)
通过缩小/缩放图像的大小，您可以摆脱内存不足异常， 试试这个
BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 6;
Bitmap receipt = BitmapFactory.decodeFile(photo.toString(),options); //From File You can customise on your needs.
答案 2 :(得分：4)
您好，您必须解码该文件。为此尝试使用以下方法。
public static Bitmap new_decode(File f) {
// decode image size
BitmapFactory.Options o = new BitmapFactory.Options();
o.inJustDecodeBounds = true;
o.inDither = false; // Disable Dithering mode
o.inPurgeable = true; // Tell to gc that whether it needs free memory,
// the Bitmap can be cleared
o.inInputShareable = true; // Which kind of reference will be used to
// recover the Bitmap data after being
// clear, when it will be used in the future
try {
BitmapFactory.decodeStream(new FileInputStream(f), null, o);
} catch (FileNotFoundException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
// Find the correct scale value. It should be the power of 2.
final int REQUIRED_SIZE = 300;
int width_tmp = o.outWidth, height_tmp = o.outHeight;
int scale = 1;
while (true) {
if (width_tmp / 1.5 < REQUIRED_SIZE && height_tmp / 1.5 < REQUIRED_SIZE)
break;
width_tmp /= 1.5;
height_tmp /= 1.5;
scale *= 1.5;
}
// decode with inSampleSize
BitmapFactory.Options o2 = new BitmapFactory.Options();
// o2.inSampleSize=scale;
o.inDither = false; // Disable Dithering mode
o.inPurgeable = true; // Tell to gc that whether it needs free memory,
// the Bitmap can be cleared
o.inInputShareable = true; // Which kind of reference will be used to
// recover the Bitmap data after being
// clear, when it will be used in the future
// return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
try {
// return BitmapFactory.decodeStream(new FileInputStream(f), null,
// null);
Bitmap bitmap= BitmapFactory.decodeStream(new FileInputStream(f), null, null);
System.out.println(" IW " + width_tmp);
System.out.println("IHH " + height_tmp);
int iW = width_tmp;
int iH = height_tmp;
return Bitmap.createScaledBitmap(bitmap, iW, iH, true);
} catch (OutOfMemoryError e) {
// TODO: handle exception
e.printStackTrace();
// clearCache();
// System.out.println("bitmap creating success");
System.gc();
return null;
// System.runFinalization();
// Runtime.getRuntime().gc();
// System.gc();
// decodeFile(f);
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
return null;
}
}
答案 3 :(得分：0)
我在另一个StackOverFlow问题中写了一个建议摘要：Android: BitmapFactory.decodeStream() out of memory with a 400KB file with 2MB free heap
答案 4 :(得分：0)
实际上问题在于开发os。在Android不像iOS，谷歌人根据相机分辨率开发此功能。位图占用大量内存，特别是对于像照片这样的丰富图像。不同的相机捕获具有不同像素的图像（不同的移动设备具有不同的相机像素容量）。在android中基于该像素，只有捕获的图像才会占用内存。所以很明显高分辨率图像不会被具有低像素容量的手机上传。 在android os中为每个应用程序分配最多16MB。如果上传的图像超过此值，那么java.lang.OutofMemoryError：位图大小将超出VM预算并且应用程序崩溃。 参考这个 http://developer.android.com/training/displaying-bitmaps/index.html
答案 5 :(得分：0)
如果你想避免使用OOM，你可以捕获OOM并增加sampleSize直到可以解析图像：
private Bitmap getBitmapSafely(Resources res, int id, int sampleSize) {
// res = context.getResources(), id = R.drawable.yourimageid
Bitmap bitmap = null;
BitmapFactory.Options options = new BitmapFactory.Options();
options.inPurgeable = true;
options.inSampleSize = sampleSize;
try {
bitmap = BitmapFactory.decodeResource(res,
id, options);
} catch (OutOfMemoryError oom) {
Log.w("ImageView", "OOM with sampleSize " + sampleSize, oom);
System.gc();
bitmap = getBitmapSafely(res, id, sampleSize + 1);
}
return bitmap;
}
希望它有所帮助。
不适合捕捉错误，只是解决方法。