摘要树问题SQL

Question

  

这是我的代码的结果，但我将总结一下例如nodid 1.1和1.2   报告：发票附录

1.   

   InvoiceNo 8027944
     ExtRef：1600056051
     订购金额3 395 300,00 kr
     Ordername注册i Fenix E
     休息：3 395 300,00 kr
     发票日期2012-11-06

2. 这是我的输出，但这不对

    Our reference   Nod_id     In nodid   amount
   1960110000       1.1        1              0,00    
   1960110001       1.1.1      1.1        29000,00       
   1960120000       1.1.2      1.1         5000,00
   1960130000       1.2        1              0,00
   1960130001       1.2.1      1.2         1920,00
   

  

1. 我有这个输出

    Our reference   Nod_id     In nodid   amount
   1960110000       1.1        1          34000,00<br>
   1960130000       1.2        1           1920,00</li>
   

        

  我的问题是我将Summury为exampel Row whit Nod_id 1.1和1.2但我将有我们的参考1960110000和描述Pos 1 ......   我的代码

sql, 1 DBSELECT 
t.project,
t.work_order as projakt,
t1.orderram,
t2.flag ,
t2.ext_inv_ref,
t2.work_order,
t2.used_hrs,
t2.cur_amount as belopp,
t4.description, 
t5.nod_id_2 as ing_nodid,
t5.nod_id_1 as nodid,
t5.ingar_pakt as namn,
t2.work_order,
SUM(t2.used_hrs) as used_hrs,
SUM(t2.cur_amount) as belopp
from  atsworkorder t
left join  afx01projact4  t5 on t.client =t5.client and t.work_order = t5.dim_value and t5.attribute_id = 'BF' 
left join afx01projact2  t1 on t.client=t1.client and t.work_order = t1.dim_value
left join atsinvhistr t2 on t.client=t2.client and t.work_order  = t2.work_order and '<datum>' >= t2.voucher_date
left join agldescription t4 on t.client =t4.client and t4.dim_value = t.work_order
where  t.project ='<proj>'  and t.client = '<client>'  
group by
t.project,
t.work_order,
t2.work_order,
t5.nod_id_1,
t5.dim_value,
t5.nod_id_2 ,
t5.ingar_pakt ,
t1.orderram,
t2.flag,
t2.ext_inv_ref,
t2.used_hrs,
t2.cur_amount,
t4.description
order by nodid