Question

抱歉，我之前在wordpress上错误地提出了这个问题。我正在进行分页，但是我遇到一个问题，当我点击下一步它会增加查询字符串中的数字以供下一页但数据在页面上保持不变，我需要显示下一条四条记录，因为我已显示每条记录4条记录页。代码似乎很好，但我不知道为什么它不工作。下面是代码

$page = 0;

if($page == 0){

    $page = "1";

}else{

    // If page is set, let's get it
  echo   $page = $_GET['page'];

}

// Now lets get all messages from your database
$sql = "select * from about_us where sbmenu_id=9991";
$query = mysql_query($sql);

// Lets count all messages
$num = mysql_num_rows($query);

// Lets set how many messages we want to display
$per_page = "4";

// Now we must calculate the last page
$last_page = ceil($num/$per_page);

// And set the first page
$first_page = "1";

// Here we are making the "First page" link
echo "<a href='?page=".$first_page."'>First page</a> ";
echo $page ;
// If page is 1 then remove link from "Previous" word
if($page == $first_page){

    echo "Previous ";

  }else{

    if(!isset($page)){

            echo "Previous";

    }else{

            // But if page is set and it's not 1.. Lets add link to previous word to take us back by one page
            $previous = $page-1;
            echo "<a href='?page=".$previous."'>Previous</a> ";

    }

 }

 // If the page is last page.. lets remove "Next" link
 if($page == $last_page){

    echo "Next ";   

  }else{

    // If page is not set or it is set and it's not the last page.. lets add link to this word so we can go to the next page
    if(!isset($page)){

            $next = $first_page+1;
            echo "<a href='?page=".$next."'>Next</a> ";

    }else{

            $next = $page+1;
            echo "<a href='?page=".$next."'>Next</a> ";

    }

 }

 // And now lets add the "Last page" link
 echo "<a href='?page=".$last_page."'>Last page</a>";

 // Math.. It gets us the start number of message that will be displayed
 $start = ($page-1)*$per_page;

 // Now lets set the limit for our query
 $limit = "LIMIT $start, $per_page";

// It's time for getting our messages
$sql = "select * from about_us where sbmenu_id=9991 $limit";
$query = mysql_query($sql);
 ?><table><?php
echo "<br /><br /><tr style='height:70px;'>";

// And lets display our messages
while($row = mysql_fetch_array($query) or die(mysql_error()))
 {....}

Answer 1

更改前几行，然后尝试..

if(isset($_GET['page']) && $_GET['page'] > 0)        // If page is set, let's get it
{
    echo   $page = $_GET['page'];  
}
else
{
    $page = 1;
}

而不是： -

$page = 0;

if($page == 0){

$page = "1";

}else{

// If page is set, let's get it
 echo   $page = $_GET['page'];

}

php分页donot显示下一条记录

1 个答案: