所以,我有一个简单的REST Web应用程序,如果我的Controller直接调用DAO,JDBC调用工作正常,但如果我的控制器调用另一个代表我调用DAO的类,它会因NullPointerException(NPE)而失败
这是我的控制器:
@Component
@Scope("request")
@Path("/emsrequest")
public class EMSRequest {
// I'm using this for testing
@GET
@Path("/xml/{accountNumber}")
@Produces({MediaType.TEXT_PLAIN})
public String requestByAccountNumber_XML(
@PathParam("accountNumber") String accountNumber) {
ReqSubTest los = new ReqSubTest();
return "account (LOS) number is : " + los.testSql(Integer.parseInt(accountNumber)) + "!";
}
}
这是中间(服务)类:
package com.company.demo.mercury.processmanager.components;
import com.company.demo.pmrws.dao.EMSRequestDaoImpl;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Component;
@Component
public class ReqSubTest {
@Autowired
EMSRequestDaoImpl dao = new EMSRequestDaoImpl();
public int testSql(int quantity){
return dao.getNextTableIds("sys_process_tbl", quantity);
}
}
这是DAO实施:
package com.company.demo.pmrws.dao;
import org.apache.log4j.Logger;
import org.springframework.jdbc.core.support.JdbcDaoSupport;
public class EMSRequestDaoImpl extends JdbcDaoSupport {
private static final Logger logger = Logger.getLogger(EMSRequestDaoImpl.class);
public int getNextTableIds(String tableName, int quantity) {
if (logger.isDebugEnabled()) {
logger.trace("Entering getNextTableIds");
}
if (getJdbcTemplate() == null) {
System.out.println("UH OH!");
}
String selectSql = "select next_id "
+ "from sys_key_tbl "
+ "where table_name = ? ";
String updateSql = "update sys_key_tbl "
+ "set next_id = ? "
+ "where table_name = ? and next_id = ? ";
int lastId = -1;
int updateCount = 0;
while (updateCount == 0) {
lastId = getJdbcTemplate().queryForInt(selectSql,
new Object[]{tableName});
updateCount = getJdbcTemplate().update(updateSql,
new Object[]{lastId + quantity, tableName, lastId});
}
if (logger.isDebugEnabled()) {
logger.trace("Leaving getNextTableIds");
}
return lastId + 1;
}
}
应用程序上下文XML:
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd">
<context:component-scan base-package="com.company.demo.pmrws"/>
<bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close">
<property name="driverClassName" value="com.sybase.jdbc3.jdbc.SybDataSource" />
<property name="url"
value="jdbc:sybase:Tds:blah:10240/BLAH_DB1" />
<property name="username" value="blah" />
<property name="password" value="blah" />
</bean>
<bean id="dataSourceMain" class="org.apache.commons.dbcp.BasicDataSource"
destroy-method="close">
<property name="driverClassName" value="com.sybase.jdbc3.jdbc.SybDataSource" />
<property name="url"
value="jdbc:sybase:Tds:blah:10240/BLAH_DB2" />
<property name="username" value="blah" />
<property name="password" value="blah" />
</bean>
</bean>
<!-- <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate">
<property name="dataSource" ref="dataSource" />
</bean>-->
<bean id="emsResponseDao" class="com.company.demo.pmrws.dao.EMSResponseDaoImpl">
<property name="dataSource" ref="dataSource" />
</bean>
<bean id="emsStatusDao" class="com.company.demo.pmrws.dao.EMSStatusDaoImpl">
<property name="dataSource" ref="dataSourceMain" />
</bean>
<!-- <bean id="collateralSybaseEmsDao" class="com.company.demo.dao.CollateralSybaseEmsDaoImpl">
<property name="dataSource" ref="dataSource" />
</bean>
<bean id="collateralSybaseDao" class="com.company.demo.dao.CollateralSybaseDaoImpl">
<property name="dataSource" ref="dataSource" />
</bean>-->
<bean id="emsRequestDao" class="com.company.demo.pmrws.dao.EMSRequestDaoImpl">
<property name="dataSource" ref="dataSource" />
</bean>
<context:component-scan base-package="com.company.demo.mercury.processmanager.components" />
</beans>
我错过了什么?顺便说一句,这是Spring 2.5。
答案 0 :(得分:3)
这是因为ReqSubTest los = new ReqSubTest();
创建了一个新的普通java Object实例而不是Spring Bean,因此没有任何内容注入los
实例。
解决它的三种方法。
ReqSubTest los = new ReqSubTest();
通过Spring注入los
,但这要求EMSRequest
也是一个Spring bean 示例:
@Component public class EMSRequest {
@Autowire ReqSubTest los;
public String requestByAccountNumber_XML(@PathParam("accountNumber") String accountNumber) {
return "account (LOS) number is : " + los.testSql(Integer.parseInt(accountNumber)) + "!";
}
}
ReqSubTest los = new ReqSubTest();
使用ReqSubTest los = springApplicationContext.getBean(ReqSubTest.class)
@Configurable
然后Spring注入其他bean即使通过new
创建实例(需要通过<context:spring-configured />
启用) - 您可以将注释添加到EMSRequest
,然后在第一项中使用正常注入,例如suggeted,或将其添加到ReqSubTest
答案 1 :(得分:0)
我想我已经找到了问题所在。问题出在您的服务类ReqSubTest
中。
你已经在那里自动安装了DAO类,但你不应该在那里初始化它。所以只需删除DAO声明的初始化部分,就可以了。所以现在你在服务类中的声明将如下所示。
@Autowired
private EMSRequestDaoImpl dao;
在您的控制器中,您还需要自动装配Service类。并且不要在函数本身中创建它的新对象。
@Autowired
private ReqSubTest service;
希望这会对你有所帮助。欢呼声。