Question

我有一个NSString，其格式为@“2013-01-09 06:10:10 +0000”（我从服务器获取它，它不是当前时间）。我想连续增加一秒钟。我可以用一个计时器来做，但如何将时间增加一秒？

Answer 1

试试这个，

NSDate *correctDate = [NSDate dateWithTimeInterval:1.0 sinceDate:yourDate];

您可以使用NSDateFormatter从字符串中获取日期。

Answer 2

在您的约会中添加1秒钟，如下所示..

NSDate *mydate = [NSDate date];
NSTimeInterval secondsInEightHours = 60; // you can add hours and minuts with multiply the numbers with this second..
NSDate *dateEightHoursAhead = [mydate dateByAddingTimeInterval:secondsInEightHours];

Answer 3

如今（2017）Apple建议将(NS)Calendar用于各种日期数学

<强>目标C

NSDate *now = [NSDate date];
NSCalendar *currentCalendar = [NSCalendar currentCalendar];
NSDate *nowPlusOneSecond = [currentCalendar dateByAddingUnit:NSCalendarUnitSecond 
                                                       value:1 
                                                      toDate:now 
                                                     options:NSCalendarMatchNextTime];

Swift 3

let now = Date()
let currentCalendar = Calendar.current
let nowPlusOneSecond = currentCalendar.date(byAdding: .second, value: 1, to: now)!

Answer 4

假设你的日期字符串在var中，称为serverString。你可以用这种方式约会......

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"yyyy-MM-dd hh:mm:ss z"];
NSDate *date = [df dateFromString:serverString];

以这种方式递增：

date = [date dateByAddingTimeInterval:1.0];

Answer 5

SWIFT 3.x解决方案

# table1
ID|URLS     | NAME      | ADDRESS    |
0 |foo.com  | foo       | foo 1      |
1 |bar.com  | bar       | bar 1      |

如何通过NSDate对象增加一秒

5 个答案: