如果我有一些xml:
<Users>
<User>
<property1>sdfd</property1>
...
<User>
...
</Users>
我的sql是:
SELECT
*
FROM
OpenXML(@idoc, '/Users/User')
WITH (
[property1] varchar(50) 'property1',
...
)
如何获取父元素的名称并将其返回到数据集中?
答案 0 :(得分:1)
来自MSDN docs on OpenXML的此页面似乎表明您应该能够为父母使用“..”表示法:
declare @idoc int
declare @doc varchar(1000)
set @doc ='<ROOT>
<Customer CustomerID="VINET" ContactName="Paul Henriot">
<Order OrderID="10248" CustomerID="VINET" EmployeeID="5"
OrderDate="1996-07-04T00:00:00">
<OrderDetail ProductID="11" Quantity="12"/>
<OrderDetail ProductID="42" Quantity="10"/>
</Order>
</Customer>
<Customer CustomerID="LILAS" ContactName="Carlos Gonzlez">
<Order OrderID="10283" CustomerID="LILAS" EmployeeID="3"
OrderDate="1996-08-16T00:00:00">
<OrderDetail ProductID="72" Quantity="3"/>
</Order>
</Customer>
</ROOT>'
--Create an internal representation of the XML document.
exec sp_xml_preparedocument @idoc OUTPUT, @doc
-- SELECT stmt using OPENXML rowset provider
SELECT *
FROM OPENXML (@idoc, '/ROOT/Customer/Order/OrderDetail',2)
WITH (OrderID int '../@OrderID',
CustomerID varchar(10) '../@CustomerID',
OrderDate datetime '../@OrderDate',
ProdID int '@ProductID',
Qty int '@Quantity')
这也适用于你的情况吗?
<强>更新强>
试试这个(“伪属性”@mp:parentlocalname):
SELECT *
FROM OPENXML (@idoc, '/ROOT/Customer/Order/OrderDetail',2)
WITH (OrderID int '../@OrderID',
CustomerID varchar(10) '../@CustomerID',
OrderDate datetime '../@OrderDate',
ProdID int '@ProductID',
Qty int '@Quantity',
ParentNodeName varchar(50) '@mp:parentlocalname' )
这个现在可以做你想要的吗? :-)
在此article at ExtremeExperts中查看这些“伪属性”的完整列表。
马克