切换具有相同类名的元素仅对于单击的可见/不可见

Question

<ul>
  <li>
    <div class="single-toggle">|Toggle|</div>
    <div class="visible-when-folded">
      <div class="name">Peter</div>
      <div class="date">3 january 1984</div>
    </div>
    <div class="invisible-when-folded">
      <div class="about">Funny guy</div>
      <div class="contact_info">0879876745</div>
    </div>
  </li>

  <li>
    <div class="single-toggle">|Toggle|</div>
    <div class="visible-when-folded">
      <div class="name">David</div>
      <div class="date">17 April 1988</div>
    </div>
    <div class="invisible-when-folded">
      <div class="about">Jackass</div>
      <div class="contact_info">0979876345</div>
    </div>    
  </li>
</ul>

期望的结果

当我点击|Toggle|元素时，只有div.invisible-when-folded内的元素会在相应的li元素中消失。

我尝试了什么

点击this code中的|Toggle|，同时切换两个li元素中不可见/可见的div。如何让它仅切换我点击的切换的li？

Answer 1

选择该类的被点击元素的所有（以下）兄弟：

$(this).nextAll('.invisible-when-folded').toggle();

DEMO

看一下jQuery的traversal methods.

Answer 2

怎么样：

$(".single-toggle").click(function(){ 
  $(this).closest('li').find('.invisible-when-folded').toggle(); 
});