您好我想将文件复制到目录中的所有文件夹
我的根文件夹树是
我想将根文件夹中的文件复制到每个目标文件夹
文件夹结构
答案 0 :(得分:1)
由于你有一个静态的文件夹结构,我建议只将不同的子文件夹存储在一个数组中,然后将其循环到copy
文件
$rootpath = ".";
$destpaths = array("/Folder1/Subfolder1/AnotherSubFolder/Target/",
"/Folder2/Subfolder1/AnotherSubFolder/Target/",
"/Folder3/Subfolder1/AnotherSubFolder/Target/",
"/Folder4/Subfolder1/AnotherSubFolder/Target/",
"/Folder5/Subfolder1/AnotherSubFolder/Target/",
"/Folder6/Subfolder1/AnotherSubFolder/Target/",
"/FolderN/Subfolder1/AnotherSubFolder/Target/");
$file = '/example.txt';
$copyfrom = $rootpath . $file;
foreach($destpaths as $destpath)
{
$copyto = $rootpath . $destpath . $file;
if (!copy($copyfrom, $copyto)) {
echo "failed to copy $file";
}
}
正如Aaron W.建议 并使用glob-php来获取递归路径(folder1,folder2 ......) 我将此代码和文件放在同一文件夹中并将其放在与folder1,folder2相同的根路径中...
$rootpath = "..";
$frompath = ".";
$file = '/example.txt';
$tosubpath="/Subfolder1/AnotherSubFolder/Target/";
$copyfrom = $frompath . $file;
listdirs($rootpath,$copyfrom,$tosubpath,$file);
function listdirs($dir,$copyfrom,$tosubpath,$file) {
$dirs = glob($dir . '/*', GLOB_ONLYDIR);
foreach($dirs as $destpath)
{
$copyto = $destpath. $tosubpath . $file;
if (!copy($copyfrom, $copyto)) {
echo "failed to copy ".$copyfrom." to".$copyto."<br>";
}else{
echo $copyfrom." copied to".$copyto."<br>";
}
}
}