我尝试在ListView中设置单个项目的动画，我发现这有点难。但是，经过一些谷歌搜索，我想出了一些我合并的代码片段，但是当我尝试调用我的ListView的{{1}}以返回视图时，返回null。
getChildAt来自代码：
public void animateSingleItemInListView() {
final Animation animBounce = AnimationUtils.loadAnimation(context, R.anim.bounce);
int totalItemsInListView = lastCases.getCount();
int wantedPosition = 1; // Whatever position you're looking for
int firstPosition = lastCases.getFirstVisiblePosition() - lastCases.getHeaderViewsCount(); // This is the same as child #0
int wantedChild = wantedPosition - firstPosition;
// Say, first visible position is 8, you want position 10, wantedChild will now be 2
// So that means your view is child #2 in the ViewGroup:
int childs = lastCases.getChildCount();
if (wantedChild < 0) {
Log.w("UPDATEUI", "Unable to get view for desired position, because it's not being displayed on screen.");
return;
}
// Could also check if wantedPosition is between listView.getFirstVisiblePosition() and listView.getLastVisiblePosition() instead.
View wantedView = lastCases.getChildAt(firstPosition);
wantedView.setAnimation(animBounce);
}
返回10，这是我totalItemsInListView中的正确行数。整数ListView当然是0，但firstPosition方法只返回null。怎么会？如何从getChildAt()获取第一个View？
答案 0 :(得分：-1)
尝试使用
lastCases.getItemAtPosition(firstPosition)