Question

我尝试安装Yahoo BOSS mashup框架，但运行提供的示例时遇到问题。实施例1,2,5和6起作用，但是3＆amp; 4给出Expat错误。这是ex3.py的输出：

gpython examples/ex3.py
    examples/ex3.py:33: Warning: 'as' will become a reserved keyword in Python 2.6
Traceback (most recent call last):
  File "examples/ex3.py", line 27, in <module>
    digg = db.select(name="dg", udf=titlef, url="http://digg.com/rss_search?search=google+android&area=dig&type=both&section=news")
  File "/usr/lib/python2.5/site-packages/yos/yql/db.py", line 214, in select
    tb = create(name, data=data, url=url, keep_standards_prefix=keep_standards_prefix)
  File "/usr/lib/python2.5/site-packages/yos/yql/db.py", line 201, in create
    return WebTable(name, d=rest.load(url), keep_standards_prefix=keep_standards_prefix)
  File "/usr/lib/python2.5/site-packages/yos/crawl/rest.py", line 38, in load
    return xml2dict.fromstring(dl)
  File "/usr/lib/python2.5/site-packages/yos/crawl/xml2dict.py", line 41, in fromstring
    t = ET.fromstring(s)
  File "/usr/lib/python2.5/xml/etree/ElementTree.py", line 963, in XML
    parser.feed(text)
  File "/usr/lib/python2.5/xml/etree/ElementTree.py", line 1245, in feed
    self._parser.Parse(data, 0)
    xml.parsers.expat.ExpatError: syntax error: line 1, column 0

在尝试查询Digg.com时，两个示例似乎都失败了。这是在ex3.py的代码中构造的查询：

diggf = lambda r: {"title": r["title"]["value"], "diggs": int(r["diggCount"]["value"])}
digg = db.select(name="dg", udf=diggf, url="http://digg.com/rss_search?search=google+android&area=dig&type=both&section=news")

Answer 1

问题是digg搜索字符串。它应该是“s =”。不是“search =”

Answer 2

我认为在示例中必须是错误：它获得了JSON结果（实际上，如果您在浏览器中复制并粘贴该URL，则会下载以

开头的文件名search.json）

{"results":[{"profile_image_url":
"http://a3.twimg.com/profile_images/255524395/KEN_OMALLEY_REVISED_normal.jpg",
"created_at":"Mon, 14 Sep 2009 14:52:07 +0000","from_user":"twilightlords",

即。完全正常的JSON;但是，它不是用json或simplejson等模块解析它，而是尝试将其解析为XML - 显然这种尝试失败了。

我相信修复（可能需要引起维护代码的人注意，以便他们可以合并它）要么是要求XML而不是JSON输出，要么用适当的方法解析生成的JSON而不是试图将其视为XML（不确定如何最好地实现任何更改，因为我不熟悉该代码）。

Yahoo BOSS Python Library，ExpatError

2 个答案: