在我的应用程序中,我总是在互联网的帮助下连接到openfire服务器。现在,如果连接丢失或断开连接,我希望它应该弹出一个按钮,然后按下OK按钮它应该重新登录该人(当与服务器的连接丢失时 - 即使1秒钟,该人也是断开连接)。
我使用以下代码:
public class ConnectionCheck extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
// TODO Auto-generated method stub
ConnectivityManager connectivityManager = (ConnectivityManager)context.getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo activeNetInfo = connectivityManager.getActiveNetworkInfo();
NetworkInfo mobileNetInfo = connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
if(activeNetInfo!=null){
Toast.makeText( context, "Active Network Type : " + activeNetInfo.getTypeName(), Toast.LENGTH_SHORT ).show();
}
if( mobileNetInfo != null )
{
Toast.makeText( context, "Mobile Network Type : " + mobileNetInfo.getTypeName(), Toast.LENGTH_SHORT ).show();
}
}
假设当wifi断开连接时,它再次连接到移动网络(但内部用户未连接到服务器)
我应该怎样做同样的事情,即当用户断开连接时 - 即使是服务器一秒钟,它也应该弹出一个。
有可能吗?
由于
答案 0 :(得分:4)
- 您的上述代码只会检查您的Android设备与 wifi路由器或手机的数据包服务的连接性,但不会检查wifi是否确实有互联网连接正常工作。
- 当我在一个项目上工作时,我曾经找到过这个解决方案,我试着通过stackoverflow查找解决方案,但我得到的就是你的代码片段。 所以我创建了自己的解决方案。
我需要做一些自定义工作..但是把它运行起来......
我的代码在关闭时从Wifi切换到移动网络。
我正在使用端口37的TimeService知道互联网是DEAD而wifi连接仍然是ON
现在我在这里提供一个完整的工作代码。请原谅我DRY
(不要重复自己原则)在这里被滥用。因此,请在生产网络中使用时重构代码并将重复代码转换为方法,即转换为single sensible place
/////---------------------------Intial Available Network Checking
private boolean checkConnection(){
boolean connected = false;
ConnectivityManager cm = (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE);
if (cm != null) {
NetworkInfo[] netInfo = cm.getAllNetworkInfo();
for (NetworkInfo ni : netInfo) {
if ((ni.getTypeName().equalsIgnoreCase("WIFI")
|| ni.getTypeName().equalsIgnoreCase("MOBILE"))
& ni.isConnected() & ni.isAvailable()) {
connected = true;
}
}
}
return connected;
} /////---------------------------Intial Available Network Checking
///// -------------------------------检查有效的Internet连接
public boolean inetAddr(){
boolean x1 = false;
try {
Socket s = new Socket("utcnist.colorado.edu", 37);
InputStream i = s.getInputStream();
Scanner scan = new Scanner(i);
while(scan.hasNextLine()){
System.out.println(scan.nextLine());
x1 = true;
}
} catch (Exception e) {
x1 = false;
}
return x1;
}
/////-------------------------------Check for the working Internet Connection
////-------------------------------Check Mobile Conectivity Again
public boolean mobileConnect(){
boolean conn = false;
ConnectivityManager cm = (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo activeNet = cm.getNetworkInfo(ConnectivityManager.TYPE_MOBILE);
if(activeNet != null){
conn = true;
}else{
conn = false;
}
return conn;
}
////------------------------------Check Mobile Conectivity Again
我在这里使用上述方法....
try{
if (!checkConnection()){
AlertDialog.Builder myAlertDialog = new AlertDialog.Builder(YumZingSplashActivity.this);
myAlertDialog.setTitle("--- Connectivity Check ---");
myAlertDialog.setMessage("No Internet Connectivity");
myAlertDialog.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
YumZingSplashActivity.this.finish();
//splashHandler.removeCallbacks(launcherRunnable);
}});
System.out.println("No Internet Connectivity");
myAlertDialog.show();
}
else{
if(inetAddr()){
aphandle = APIHandling.getInstance();
aphandle.xmlCreateSession();
System.out.println("Net Connectivity is Present");
DURATION = Integer.valueOf(getString(R.string.splash_duration));
splashHandler = new Handler();
// ================ Main Code of the Application
launcherRunnable = new Runnable() {
public void run() {
Intent i = new Intent(YumZingSplashActivity.this, YumZingTabHostActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(i);
YumZingSplashActivity.this.finish();
}
};
if (DEBUG)
{
splashHandler.post(launcherRunnable);
}
else{
splashHandler.postDelayed(launcherRunnable, DURATION);
}
}
else{
if(mobileConnect()){
if(inetAddr()){
aphandle = APIHandling.getInstance();
aphandle.xmlCreateSession();
System.out.println("Net Connectivity is Present");
DURATION = Integer.valueOf(getString(R.string.splash_duration));
splashHandler = new Handler();
// ================ Main Code of the Application
launcherRunnable = new Runnable() {
public void run() {
Intent i = new Intent(YumZingSplashActivity.this, YumZingTabHostActivity.class);
i.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
startActivity(i);
YumZingSplashActivity.this.finish();
}
};
if (DEBUG)
{
splashHandler.post(launcherRunnable);
}
else{
splashHandler.postDelayed(launcherRunnable, DURATION);
}
}else{
AlertDialog.Builder myAlertDialog = new AlertDialog.Builder(YumZingSplashActivity.this);
myAlertDialog.setTitle("--- Connectivity Check ---");
myAlertDialog.setMessage("No Internet Connectivity");
myAlertDialog.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
YumZingSplashActivity.this.finish();
//splashHandler.removeCallbacks(launcherRunnable);
}});
System.out.println("No Internet Connectivity");
myAlertDialog.show();
}
}else{
AlertDialog.Builder myAlertDialog = new AlertDialog.Builder(YumZingSplashActivity.this);
myAlertDialog.setTitle("--- Connectivity Check ---");
myAlertDialog.setMessage("No Internet Connectivity");
myAlertDialog.setPositiveButton("OK", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface arg0, int arg1) {
YumZingSplashActivity.this.finish();
//splashHandler.removeCallbacks(launcherRunnable);
}});
System.out.println("No Internet Connectivity");
myAlertDialog.show();
}
}
}
//setContentView(R.layout.yumzing_splash_layout);
} catch(Exception ex){
System.out.println("Leak ko catch");
}
}
答案 1 :(得分:1)