Question

我使用复选框组合过滤器（使用jquery UI设置样式），组和哈希历史记录，将同位素作为产品排序矩阵工作。总而言之，一切都按预期工作，结果非常好。我遇到了一个问题，我需要根据某些复选框重新排序过滤结果。如果你看一下这里的小提琴：http://jsfiddle.net/rwbennet/B8kV3/2/你可以看到我的结果。问题是，如果您向下滚动到复选框并选择“Wellness Incentives”，我需要在结果中首先显示所有“Mastercard”标记结果。所以作为一个基本的排序，一切都只是字母顺序，如果你选择一些复选框，结果只保持字母顺序，但如果你选择“健康激励”作为“使用”之一，结果应该重新排序并从“万事达卡”开始“结果。还有其他例外，但这只是一个例子。有没有办法做我在这里解释建立在同位素中的东西？非常感谢您对此问题的任何考虑。

目前，这是我的同位素代码：

 var $container = $('#container');
 var $filterDisplay = $('#filter-display');

 // Initiate Isotope and pass in hash change filter
 $container.isotope({
    filter: hashfilter
 });

 if( location.hash != "" ){
   var hashfilter = location.hash.substr( 1 );
 } else {
   var hashfilter = "*";
 }

 var filters = {};

 isOptionLinkClicked = false;

 $('#options').on( 'change', function( jQEvent ) {

   var checkbox = jQEvent.target;
   var $checkbox = $( checkbox );
   var value = checkbox.value;
   var group = $checkbox.parents('.option-set').attr('data-group');

   // create array for filter group, if not there yet
   if ( !filters[ group ] ) {
     filters[ group ] = [];
   }

var index = $.inArray( checkbox.value, filters[ group ] );

if ( checkbox.checked ) {
  var selector = 'input';
  $checkbox.siblings( selector ).removeAttr('checked');


  if ( index === -1 ) {
    // add filter to group
    filters[ group ].push( checkbox.value );
    isOptionLinkClicked = true;
    $(this).data('clicked', true);
    //console.log($(this).data());
  }

  } else {
    // remove filter from group
    filters[ group ].splice( index, 1 );

  }


   var i = 0;
   var comboFilters = [];

  for ( var prop in filters ) {
    var filterGroup = filters[ prop ];

    // skip to next filter group if it doesn't have any values
    if ( !filterGroup.length ) {
      continue;
    }

    if ( i === 0 ) {
      // copy to new array
      comboFilters = filterGroup.slice(0);

    } else {

    var filterSelectors = [];

    // copy to fresh array
    var groupCombo = comboFilters.slice(0); // ex: [ A, B ]

    // merge filter Groups
    for (var k=0, len3 = filterGroup.length; k < len3; k++) {

      for (var j=0, len2 = groupCombo.length; j < len2; j++) {
        filterSelectors.push( groupCombo[j] + filterGroup[k] ); // [ 1, 2 ]
      }

    }

    // apply filter selectors to combo filters for next group
    comboFilters = filterSelectors
  }
  i++

  location.hash = comboFilters.join(', ');

  var hashObject = location.hash.replace( /^#/, '' );

  //return false;
}

$container.isotope({ filter: comboFilters.join(', ') });

// Helpful for messing with hashchange URLs
//$filterDisplay.text( comboFilters.join(', ') );

});

var hashObject = location.hash.replace( /^#/, '' );
var hashChanged = false;

$(window).bind( 'hashchange', function( event ){

if(location.hash != "") {
    var hashfilter = location.hash.substr(1);
} else {
    var hashfilter = "*";
}

$container.isotope({
    filter: hashfilter
});

})

// trigger hashchange to capture initial hash options
.trigger( 'hashchange' );

// trigger ui clicks to mirror initial hash options
var strHash = location.hash.substr(1); // Get our url hash
var arHash = strHash.split(" ").join("").split(",").join("").split("."); 
// get rid of the spaces, commas, and conver to an array
var arHashUnique = Array(); // remove duplicates from the array
$.each(arHash, function(i, item){
   if($.inArray(item, arHashUnique) === -1 && item != "") 
   {
      arHashUnique.push(item);
   }
});

for(var i in arHashUnique) // click the appropriate filters {
  $("#" + arHashUnique[i]).click();
}

筛选结果上的jquery同位素排序异常

0 个答案: