Question

class BookMe(Handler):
    def render_book(self, deal=""):
        deals = db.GqlQuery("SELECT * FROM Book ORDER BY created DESC")
        self.render("book.html", deal=deal,deals = deals)

    def get(self):
        render_book()

    def post(self):
        deal = self.request.get("deal")
        if deal:
            b = Book(deal = deal)
            b.put()
            self.redirect("/")

app = webapp2.WSGIApplication([('/', MainPage),
                           ('/unit2/rot13', Rot13),
                           ('/book', BookMe),
                           ('/unit2/signup', Unit2Signup),
                           ('/unit2/welcome', Welcome),
                           ('/blog/?', BlogFront),
                            ],debug=True)

我指示'book'映射到BookMe处理程序，但是当我键入/ book时它会引发404并且/ book与应用程序配置中的任何模式都不匹配。

任何人都可以给我一个提示吗？

这是我的app.yaml

application: byrdnee
version: 1
runtime: python27
api_version: 1
threadsafe: true

handlers:
- url: /.*
  script: blog.app

libraries:
- name: jinja2
  version: latest

我的主文件名是blog.py

Answer 1

我没有完整的代码，但以下内容应该有效

import webapp2
from google.appengine.ext.webapp import template

class BookMe(webapp2.RequestHandler):
    def get(self):
        deals = db.GqlQuery("SELECT * FROM Book ORDER BY created DESC")
        template_values = {
            'deals': deals,
        }

    self.response.write(template.render("book.html", template_values))

为什么网址映射无法在Google应用引擎上显示404？

1 个答案: