Question

我有多个对象和多个容器，我的计划是任何对象都可以放在任何容器上，但是一旦容器上放有一个对象，我希望它被占用，不再允许任何对象进入它。是否有一个isOcuppied电话或类似的东西，我找不到任何这方面的例子。

    local function onTouch( event )
local t = event.target

local phase = event.phase
if "began" == phase then
    -- Make target the top-most object
    local parent = t.parent
    parent:insert( t )
    display.getCurrentStage():setFocus( t )


    -- Spurious events can be sent to the target, e.g. the user presses 
    -- elsewhere on the screen and then moves the finger over the target.
    -- To prevent this, we add this flag. Only when it's true will "move"
    -- events be sent to the target.
    t.isFocus = true

    -- Store initial position
    t.x0 = event.x - t.x
    t.y0 = event.y - t.y
elseif t.isFocus then
    if "moved" == phase then
        -- Make object move (we subtract t.x0,t.y0 so that moves are
        -- relative to initial grab point, rather than object "snapping").
        t.xScale = 1.7
        t.yScale = 1.7
        t.x = event.x - t.x0
        t.y = event.y - t.y0
        --t1 = t1..t.value
    elseif "ended" == phase or "cancelled" == phase then
    for i = 1, #posX do
     if (((t.x >= ((sizeX/2) + posX[i] - ((2/3) * sizeX))) and (t.y >= ((sizeY/2) + posY - ((1/3) * sizeY))) and (t.x <= ((sizeX/2) + posX[i] + ((2/3) * sizeX))) and (t.y <= ((sizeY/2) + posY + ((1/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX[i] - ((1/3) * sizeX))) and (t.y >= ((sizeY/2) + posY - ((2/3) * sizeY))) and (t.x <= ((sizeX/2) + posX[i] + ((1/3) * sizeX))) and (t.y <= ((sizeY/2) + posY + ((2/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX[i] - ((1/2) * sizeX))) and (t.y >= ((sizeY/2) + posY - ((1/2) * sizeY))) and (t.x <= ((sizeX/2) + posX[i] + ((1/2) * sizeX))) and (t.y <= ((sizeY/2) + posY + ((1/2) * sizeY))))) then
        t.x, t.y = posX[i] + (sizeX/2), posY + (sizeY/2);
     elseif  (((t.x >= ((sizeX/2) + posX1[i] - ((2/3) * sizeX))) and (t.y >= ((sizeY/2) + posY1 - ((1/3) * sizeY))) and (t.x <= ((sizeX/2) + posX1[i] + ((2/3) * sizeX))) and (t.y <= ((sizeY/2) + posY1 + ((1/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX1[i] - ((1/3) * sizeX))) and (t.y >= ((sizeY/2) + posY1 - ((2/3) * sizeY))) and (t.x <= ((sizeX/2) + posX1[i] + ((1/3) * sizeX))) and (t.y <= ((sizeY/2) + posY1 + ((2/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX1[i] - ((1/2) * sizeX))) and (t.y >= ((sizeY/2) + posY1 - ((1/2) * sizeY))) and (t.x <= ((sizeX/2) + posX1[i] + ((1/2) * sizeX))) and (t.y <= ((sizeY/2) + posY1 + ((1/2) * sizeY))))) then
        t.x, t.y = posX1[i] + (sizeX/2), posY1 + (sizeY/2);
        t2[i] = t.value
        --t1 = t1..t.value
     -- elseif  (((t.x >= ((sizeX/2) + posX2 - ((2/3) * sizeX))) and (t.y >= ((sizeY/2) + posY2 - ((1/3) * sizeY))) and (t.x <= ((sizeX/2) + posX2 + ((2/3) * sizeX))) and (t.y <= ((sizeY/2) + posY2 + ((1/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX2 - ((1/3) * sizeX))) and (t.y >= ((sizeY/2) + posY2 - ((2/3) * sizeY))) and (t.x <= ((sizeX/2) + posX2 + ((1/3) * sizeX))) and (t.y <= ((sizeY/2) + posY2 + ((2/3) * sizeY)))) or ((t.x >= ((sizeX/2) + posX2 - ((1/2) * sizeX))) and (t.y >= ((sizeY/2) + posY2 - ((1/2) * sizeY))) and (t.x <= ((sizeX/2) + posX2 + ((1/2) * sizeX))) and (t.y <= ((sizeY/2) + posY2 + ((1/2) * sizeY))))) then
        -- t.x, t.y = posX2 + (sizeX/2), posY2 + (sizeY/2);
    end
    end
        t1 = t1..t.value
        t.xScale = 1
        t.yScale = 1
        --print(tile.label)
        display.getCurrentStage():setFocus( nil )
        t.isFocus = false
        --n = n + 1
        --value = " "
    end
end

这是我的代码，因为它我也有一个值附加到每个瓷砖，例如瓷砖a =“A”，目前我只是在每次移动瓷砖时附加一个字符串，但我想要字符串或也可以使用一个表，只有在将瓷砖放入容器时才附加。例如，如果一个字母位于错误的位置并且我将它移动到正确的位置，我已经触摸了两次，所以我的最终字符串将是错误的

Answer 1

为什么不在容器上设置一个值：

myContainer.isOccupied = false

然后在您的事件处理程序中，当您进入结束阶段时，您只需进行检查：

if not myContainer.isOccupied then
    -- code to drop
    myContainer.isOccupied = true
end

将对象拖到容器上并标记为已占用

1 个答案: