Java意外输出

Question

有些人可以解释我是如何得到这个答案的：

  

三次二= 6

代码：

public class Params1 {
    public static void main(String[] args) {
        String one = "two";
        String two = "three";
        String three = "1";
        int number = 20;
        sentence(one, two, 3);
    }

    public static void sentence(String three, String one, int number) {
        String str1 = one + " times " + three + " = " + (number * 2);
    }

}

Answer 1

这是一个有用的图表：

我希望它清楚。

以下是如何让同样的代码更容易混淆：

    public static void main(String[] args) {
        String a = "three";
        String b = "two";
        sentence(a, b, 3);
    }

    public static void sentence(String a, String b, int number) {
        String str1 = a + " times " + b + " = " + (number * 2);
        System.out.println(str1); // to let you inspect the value
    }

Answer 2

致电sentence()

sentence(one, two, 3);

为了论证，只需要替换所有变量及其值：

sentence( "two", "three", 3);

然后看一下该函数内部参数的值：

three == "two"
one == "three"
number == 3

然后替换你生成的句子中的参数，你就得到了结果！

此外，您的变量名称实际上并不是不言自明的。你应该重新考虑它们以防止这种误解。

Answer 3

很难猜到你想要在这里实现什么。当然，您不希望将“字符串”文字解释为实际数值......

更正您的变量值：

String one = "one";
String two = "two";

和

sentence(three, one, 3);

和

public static void sentence(String three, String one, int number) {
    String str1 = one + " times " + three + " = " + (number);
}

Answer 4

你给3作为'句子'方法的参数。

sentence(one, two, 3);

将其更改为

sentence(one, two, number);

Answer 5

String str1 = one + " times " + three + " = " + (number * 2);

此处one == two ==“三”

和three == one ==“两个”

和number == 3

所以你得到了那个。 你推荐的更好：JAVA methods help