我在Word pad(文本后面的新行)中获得了完美的结果但是我无法使用以下代码在记事本中获得新行。并且希望得到与填充文字相同的结果。
private void getIntentDetails() {
intent = getIntent();
if (intent.hasExtra("testName")) {
testName = (String) intent.getExtras().get("testName");
Log.e("testName ", "testName " + testName);
appendLog("TestName : ");
appendLog(testName);
appendLog(", ");
//appendLog("\n");
}
if (intent.hasExtra("testDate")) {
testDate = (String) intent.getExtras().get("testDate");
Log.e("testDate ", "testDate " + testDate);
appendLog("TestDate : ");
appendLog(testDate);
appendLog(", ");
}
if (intent.hasExtra("testTime")) {
testTime = (String) intent.getExtras().get("testTime");
Log.e("testTime ", "testTime " + testTime);
appendLog("TestTime : ");
appendLog(testTime);
appendLog(", ");
}
if (intent.hasExtra("savedName")) {
savedName = (String) intent.getExtras().get("savedName");
Log.e("savedName ", "savedName " + savedName);
appendLog("SavedName : ");
appendLog(savedName);
appendLog(", ");
}
if (intent.hasExtra("sensitivity")) {
sensitivity = (String) intent.getExtras().get("sensitivity");
Log.e("sensitivity ", "sensitivity " + sensitivity);
appendLog("Accelerometer Sensitivity : ");
appendLog(sensitivity);
appendLog(" , ");
}
if (intent.hasExtra("xvalues")) {
xValues = (ArrayList<Float>) intent.getExtras().get("xvalues");
Log.e("xValues ", "xValues " + xValues.size());
for (int indexx = 0; indexx < xValues.size(); indexx++) {
xvalue = xValues.get(indexx).toString();
if (indexx == 0) {
appendLog("X-Values : ");
}
appendLog(xvalue);
appendLog(", ");
}
}
Log.d("X-Values : ", ""+ xValues.size());
if (intent.hasExtra("yvalues")) {
yValues = (ArrayList<Float>) intent.getExtras().get("yvalues");
Log.e("yValues ", "yValues " + yValues.size());
for (int indexy = 0; indexy < yValues.size(); indexy++) {
yvalue = yValues.get(indexy).toString();
if (indexy == 0) {
appendLog("Z-Values : ");
}
appendLog(yvalue);
appendLog(", ");
}
}
Log.e("Z-Values : ", ""+ yValues.size());
if(intent.hasExtra("xpos")){
xPos = (String[]) intent.getExtras().get("xpos");
}
// for(int m = 0; m< xPos.length;m++){
// Log.d("xPos", " "+ xPos[m]);
// }
if(intent.hasExtra("xneg")){
xNeg = (String[]) intent.getExtras().get("xneg");
Log.e("xNeg ", "xNeg " + xNeg.length);
}
// for(int m = 0; m< xNeg.length;m++){
// Log.d("xNeg", " "+ xNeg[m]);
// }
if(intent.hasExtra("ypos")){
yPos = (String[]) intent.getExtras().get("ypos");
Log.e("yPos ", "yPos " + yPos.length);
}
// for(int m = 0; m< yPos.length;m++){
// Log.d("yPos", " "+ yPos[m]);
// }
if(intent.hasExtra("yneg")){
yNeg = (String[]) intent.getExtras().get("yneg");
Log.e("yNeg ", "yNeg " + yNeg.length);
}
// for(int m = 0; m< yNeg.length;m++){
// Log.d("yNeg", " "+ yNeg[m]);
// }
}
private void appendLog(String text) {
File logFile = new File(fileLocation);
if (!logFile.exists()) {
try {
Log.e("file was not created", "file created");
logFile.createNewFile();
} catch (IOException e) {
e.printStackTrace();
}
}
try {
// BufferedWriter for performance, true to set append to file flag
BufferedWriter buf = new BufferedWriter(new FileWriter(logFile, true)/*,8192*/);
//buf.newLine();
// System.getProperty("line.separator");
buf.write(text);
//System.getProperty("line.separator");
//buf.append("\n");
//buf.write("/\n");
buf.newLine();
buf.close();
} catch (IOException e) {
e.printStackTrace();
}
}
答案 0 :(得分:0)
这是因为记事本不是富文本阅读器,它只能理解
中不是\的字符答案 1 :(得分:0)
我是使用FileOutputStream完成的。
以下代码对我有用......
try{
FileOutputStream fop = new FileOutputStream(logFile,true);
// get the content in bytes
byte[] contentInBytes = text.getBytes();
fop.write(contentInBytes);
//writing new line using bytes
String br = "\r\n";
fop.write (br.getBytes ());
fop.flush();
fop.close();
}catch (Exception e) {
e.printStackTrace();
}