我自10月以来一直在学习Python,以便从大约一百万个文本文件中提取数据。我一直试图用小巧谨慎的块来解决这个问题,这样我就不会为了一次性获得我想要的所有代码而感到不知所措。
对于我的第一个块,我想从文本文件中提取地址。到目前为止,我已经设法让我的代码一次只能处理一个文件,但由于我有超过100万个文件需要通过,我不认为手动执行此操作会有效。
为了简洁起见,我只包含了我的代码的第一部分,因为其余部分基本上是这样,但是寻找不同的关键字。
######
#Importing/creating modules
######
import os
import re
regex = re.compile('\d+')
######
#Creating N/A text for non-existing entries
######
CV2 = """N/A
N/A
"""
######
#Opening Database file
######
target = open('C:/project/database.csv', 'a')
####
#Opening the source documents
####
big_file = open('C:/project/0000068100-99-000018.txt', 'r')
####
#Looking for central key
####
for line in big_file:
if 'CENTRAL INDEX KEY:' in line:
key = regex.findall(line)
####
#Looking for Conforming Period
####
big_file = open('C:/project/0000068100-99-000018.txt', 'r')
for line in big_file:
if 'CONFORMED PERIOD OF REPORT:' in line:
conform = regex.findall(line)
#####
#Looking for File Type
#####
big_file = open('C:/project/0000068100-99-000018.txt', 'r')
for line in big_file:
if 'CONFORMED SUBMISSION TYPE:' in line:
type_temp = re.split('\s+',line)
type1 = type_temp [3]
type = type1.split()
#####
#Looking for company name
#####
big_file = open(''C:/project/0000068100-99-000018.txt', 'r')
for line in big_file:
if 'COMPANY CONFORMED NAME:' in line:
name_temp = re.split('\:+',line)
name1 = name_temp [1]
name2 = name1.split()
name3 = ' '.join(name2)
name = re.split('\::+',name3)
####
#Looking for Street and Mail Addresses
####
big_file = open('C:/project/0000068100-99-000018.txt', 'r')
f = open('C:/Users/Martin/Thesis/address1.txt', 'w+')
for line in big_file:
if 'STREET 1:' in line:
f.write(line)
f = open('C:/project/address1.txt', 'w+')
a = open('C:/project/address1a.txt', 'w+')
b = os.path.getsize('C:/project/address1.txt')
########
#If empty, return NA, if not clean unnesseary tabs and formmating from line
########
if b == 0:
a.write(CV2)
else:
for line in f:
type_temp = re.split('\:+',line)
add_temp = type_temp[1]
add_temp_temp = ''.join(add_temp)
add = re.split('\t+',add_temp_temp)
tempo = "".join(add)
a.write(tempo)
#print tempo
a = open('C:/project/address1a.txt', 'w+')
lines=a.readlines()
bus1 = lines[0]
bus2 = re.split('\n+',bus1)
bus3 = bus2 [0]
business1 = re.split('\::+',bus3)
########
#Preping for inclusion for the Database entry
########
mail1 = lines[1]
mail2 = re.split('\n+',mail1)
mail3 = mail2 [0]
mailad1 = re.split('\::+',mail3)
#####
#Formatting data tags
#####
company_name_temp = "Company Name"
company_name = re.split('\::+',company_name_temp)
bus_street1_temp = "Business Street 1"
bus_street1 = re.split('\::+',bus_street1_temp)
mstreet1_temp = key + conform + type + mail_street1 + mailad1
mstreet1 = ','.join(mstreet1_temp)
######
#Prepping for database
######
name_temp1 = key + conform + type + company_name + name
co_name = ','.join(name_temp1)
bstreet1_temp = key + conform + type + bus_street1 + business1
bstreet1 = ','.join(bstreet1_temp)
mstreet1_temp = key + conform + type + mail_street1 + mailad1
mstreet1 = ','.join(mstreet1_temp)
######
#Writing to database
######
target.write(co_name)
target.write("\n")
target.write(bstreet1)
target.write("\n")
target.write(mstreet1)
target.write("\n")
我尝试在顶部打开一次文件并多次调用该变量,但它没有用,我假设for循环看起来与此类似,但我不知道如何制作它有效。
for filename in os.listdir('C:/project'):
bigfile = filename
由于
答案 0 :(得分:0)
这是因为open
返回实际流式传输的FileObjects
,因此您无法多次访问它 - 实际上只能访问一次。你想在这里做的更像是这样:
for filename in os.listdir('C:\project'):
bigfile = open(filename, 'r').read()
# Now the file contents are saved within bigfile, and you can do as you please,
# accessing multiple times.
如果您的文件很大,则不建议这样做,因为Python需要花很多时间才能读入并保存整个文件。这就是open
流式传输文件数据的确切原因,因此您可以根据需要随时访问它,而不是被迫一次性获取整个块。
顺便说一句,您应该查看csv
模块。