Question

我有两个数组。现在我想基于我需要将一个数组元素填充到新数组来比较两个数组中的一些元素。

 Array1: $days this is an array of elements between two dates.

$days = Array
       (
         [0] => 2012-06-23
         [1] => 2012-06-24
         [2] => 2012-06-25
         [3] => 2012-06-26
         [4] => 2012-06-27
         [5] => 2012-06-28
         [6] => 2012-06-29
         [7] => 2012-06-30
         [8] => 2012-07-01
         [9] => 2012-07-02
         [10] => 2012-07-03
         [11] => 2012-07-04
         [12] => 2012-07-05
         [13] => 2012-07-06
         [14] => 2012-07-07
         [15] => 2012-07-08
         [16] => 2012-07-09
         [17] => 2012-07-10
         [18] => 2012-07-11
         [19] => 2012-07-12
         [20] => 2012-07-13
         [21] => 2012-07-14
         [22] => 2012-07-15
         [23] => 2012-07-16
        )

 Array2: $summary is the array which i am getting from the database..

 $summary = Array
 (
    [0] => Array
    (
        [date] => 2012-06-23 
        [no_of_posts] => 1
    )

    [1] => Array
    (
        [date] => 2012-06-24 
        [no_of_posts] => 2
    )

    [2] => Array
    (
        [date] => 2012-06-25 
        [no_of_posts] => 1
    )

    [3] => Array
    (
        [date] => 2012-06-26 
        [no_of_posts] => 1
    )

    [4] => Array
    (
        [date] => 2012-06-27
        [no_of_posts] => 1
    )

现在从这两个阵列我需要一个数组，告诉我在这个日期，如果没有针对一个日期的帖子那么多次帖子就在那里，那么它应该为零。我试过这个......

    $result = array();
   foreach($summary as $key=>$s) {
       foreach($days as $d) {
          if($s['date'] == $d) {
               $result[$d] = $s['no_of_posts'];
          } else {
               $result[$d] = 0;
          }
      }
   }

我知道有一个错误，我无法找到...........任何想法。

输出数组需要如下所示......

    $result = Array
            Array
       (
         [2012-06-23] = 1
         [2012-06-24] = 2
         [2012-06-25] = 1
         [2012-06-26] = 1
         [2012-06-27] = 1
         [2012-06-28] = 0
         [2012-06-29] = 0
         [2012-06-30] = 0
         [2012-07-01] = 0
         [2012-07-02] = 0
         [2012-07-03] = 0
         [2012-07-04] = 0
         [2012-07-05] = 0
         [2012-07-06] = 0
         [2012-07-07] = 0
         [2012-07-08] = 0
         [2012-07-09] = 0
         [2012-07-10] = 0
         [2012-07-11] = 0
         [2012-07-12] = 0 
         [2012-07-13] = 0
         [2012-07-14] = 0
         [2012-07-15] = 0
         [2012-07-16] = 0
        )

Answer 1

最快捷的方法是遍历数据库结果并创建一个按日期索引的值数组：

$summaryTotals = array();
foreach($summary as $dbSummary) {
    $summaryTotals[$dbSummary['date']] = $dbSummary['no_of_posts'];
}

然后遍历您的日期数组，输入在摘要数组中发生匹配的值，如下所示：

$dayValues = array();
foreach($days as $day) {
    if(isset($summaryTotals[$day])) {
        $dayValues[$day] = $summaryTotals[$day];
    } else {
        $dayValues[$day] = 0;
    }
}

dayValues数组现在应该是您所追求的。我相信。

Answer 2

尝试这种方式：

   $newArr = array();

    foreach($summary as $key=>$s) {
      $newArr[$s['date']] = $s['no_of_posts'];
    }

    $newDays = array_fill_keys(array_values($days),'0');

    $newData = $newDays + $newArr;

    print_r ($newData);

Answer 3

代码应为： $ days =数组（ 0 =＆gt; '2012-06-23'， 1 =＆gt; '2012-06-24'， 2 =＆GT; '2012-06-25'， 3 =＆GT; '2012-06-26'， 4 =＆GT; '2012-06-27'， 5 =＆GT; '2012-06-28'， 6 =＆GT; '2012-06-29'， 7 =＆GT; '2012-06-30'， 8 =＆GT; '2012-07-01'， 9 =＆GT; '2012-07-02'， 10 =＆gt; '2012-07-03'， 11 =＆gt; '2012-07-04'， 12 =＆gt; '2012-07-05'， 13 =＆gt; '2012-07-06'， 14 =＆gt; '2012-07-07'， 15 =＆gt; '2012-07-08'， 16 =＆gt; '2012-07-09'， 17 =＆gt; '2012-07-10'， 18 =＆gt; '2012-07-11'， 19 =＆gt; '2012-07-12'， 20 =＆gt; '2012-07-13'， 21 =＆gt; '2012-07-14'， 22 =＆gt; '2012-07-15'， 23 =＆gt; '2012-07-16'，）; $ summary = array （ 0 =＆gt;排列（ 'date'=＆gt; '2012-06-23'， 'no_of_posts'=＆gt; 1 ），

        1 => array
        (
            'date' => '2012-06-24' ,
            'no_of_posts' => 2
            ),

        2 => array
        (
            'date' => '2012-06-25', 
            'no_of_posts' => 1
            ),

        3 => array
        (
            'date' => '2012-06-26' ,
            'no_of_posts' => 1
            ),

        4 => array
        (
            'date' => '2012-06-27',
            'no_of_posts' => 1
            )
        );

    $result = array();
    foreach($summary as $key=>$s) {
        foreach($days as $d) {
            if($s['date'] == $d) {
                $result[$d] = $s['no_of_posts'];
            } else if(!isset($result[$d])){
                $result[$d] = 0;
            }
        }
    }

需要数组格式化帮助？

3 个答案: