我有三个表连接以下关系:
"agency" 1-n "agent" 1-n "ad"
(agency has many agents and each agent has many ads)
我希望按代理机构获取广告计数列表,如下所示:
agency_name | ad_count
---------------------------
agency 1 | 15
agency 2 | 25
agency 3 | 0
即使展示0个广告的代理商也会出现。这可能吗?非常感谢!
答案 0 :(得分:1)
由于你没有提供确切的表结构,我不得不猜一点
select agency.agency_name,
count(ad.id) as ad_count
from agency
left outer join agent on agency.id = agent.agency_id
left outer join ad on ad.id = agent.ad_id
group by agency.agency_name
答案 1 :(得分:1)
select agency.agency_name, count(ad.id)
from agency
left join agent on agent.agency_id = agency.id
left join ad on ad.agent_id = agent.id
group by agency.agency_name
答案 2 :(得分:0)
试试这个:
SELECT a.agencyname, IFNULL(b.adcnt, 0) adcount
FROM agency
LEFT JOIN (SELECT a.agencyid, SUM(adcnt) adcnt
FROM agent a
INNER JOIN (SELECT agentid, COUNT(agentid) adcnt
FROM ad
GROUP BY agentid
) b ON a.agentid = b.agentid
GROUP BY agencyid) b ON a.agencyid = b.agencyid