Question

我有一个自定义的 WP 3.5 函数，我不知道为什么它不起作用...我确定错误在SQL查询中。该函数试图做的是从特定类别获取帖子的帖子以$ post_name开头。

function get_post_like_slug($post_name) {
    global $wpdb;
    $page_name = substr($post_name, 0, -1).'%';
    $id = $wpdb->get_var( $wpdb->prepare("SELECT $wpdb->posts.ID FROM $wpdb->posts LEFT JOIN $wpdb->term_relationships ON($wpdb->posts.ID = $wpdb->term_relationships.object_id) WHERE ($wpdb->term_relationships.term_taxonomy_id = 5 AND $wpdb.post_name LIKE %s)", $post_name ));

    if ( $id )
        return ($id);

    return null;
}

Answer 1

在另一篇关于正确使用wordpress语句的帖子中看到这个。

可能是这样的：

$id = $wpdb->get_var( $wpdb->prepare("SELECT $wpdb->posts.ID FROM
  $wpdb->posts LEFT JOIN $wpdb->term_relationships ON($wpdb->posts.ID =
  $wpdb->term_relationships.object_id) WHERE
  ($wpdb->term_relationships.term_taxonomy_id = 5 AND $wpdb.post_name
  LIKE %s)", '%' . like_escape($post_name) . '%' ));

以下是帖子的链接：https://wordpress.stackexchange.com/a/8847

Answer 2

我找到了解决方案！我做的是先添加“$ wpdb-＆gt;”在每个表名和转义％字符（%%）上。以下功能现在可以使用：

function get_post_like_slug($post_name) {
    global $wpdb;
    $post_name = substr($post_name, 0, -1);
    $id = $wpdb->get_var( $wpdb->prepare("SELECT ID FROM $wpdb->posts LEFT JOIN $wpdb->term_relationships ON $wpdb->posts.ID = $wpdb->term_relationships.object_id WHERE post_name LIKE %s AND $wpdb->term_relationships.term_taxonomy_id=5 LIMIT 1", $post_name.'%%' ));

    if ( $id )
        return ($id);
    return null;
}

Wordpress自定义函数get_post_like_slug无法正常工作？

2 个答案: