所以我试图在一个大的C ++ STL向量上执行递归(一个非常简单的分裂基数递归蝴蝶的代码),我使用迭代器来调用递归,但它不能正常工作,因为我一直在收到错误。
#include <iostream>
#include <cmath>
#include <vector>
#include <string>
#include <algorithm>
using namespace std;
template <typename T>
class fft_data{
public:
vector<T> re;
vector<T> im;
};
void inline split_radix_rec(vector<double>::iterator r,vector<double>::iterator i, int sgn,int N) {
if (N == 1) {
return;
} else if (N == 2) {
for (int k = 0; k < N/2; k++) {
int index = 2*k;
int index1 = index+1;
double taur = *(r+index1);
double taui = *(i+index1);
*(r+index1) = *(r+index) - taur;
*(i+index1) = *(i+index) - taui;
*(r+index) = *(r+index) + taur;
*(i+index) = *(i+index) + taui;
}
N=N/2;
} else {
int m = N/2;
int p = N/4;
double PI2 = 6.28318530717958647692528676655900577;
double theta = -1.0 * sgn * PI2/N;
double S = sin(theta);
double C = cos(theta);
double PI6 = 3.0*6.28318530717958647692528676655900577;
double theta3 = -1.0 * sgn * PI6/N;
double S3 = sin(theta3);
double C3 = cos(theta3);
double wlr = 1.0;
double wli = 0.0;
//T wl2r = (T) 1.0;
//T wl2i = (T) 0.0;
double wl3r = 1.0;
double wl3i = 0.0;
double tau1r,tau1i,tau2r,tau2i;
double ur,ui,vr,vi;
for (int j = 0; j < p; j++) {
int index1 = j+m;
int index2 = index1+p;
int index3 = j+p;
tau1r = *(r+index1);
tau1i = *(i+index1);
tau2r = *(r+index2);
tau2i = *(i+index2);
ur = tau1r + tau2r;
ui = tau1i + tau2i;
vr = sgn* (tau2r - tau1r);
vi = sgn* (tau2i - tau1i);
*(r+index2) = *(r+index3) - vi;
*(i+index2) = *(i+index3) + vr;
*(r+index1) = *(r+j) - ur;
*(i+index1) = *(i+j) - ui;
*(r+index3) = *(r+index3) + vi;
*(i+index3) = *(i+index3) - vr;
*(r+j) = *(r+j) + ur;
*(i+j) = *(i+j) + ui;
}
split_radix_rec(r.begin(),i.begin(),sgn,m);
split_radix_rec(r.begin()+m,i.begin()+m,sgn,p);
split_radix_rec(r.begin()+m+p,i.begin()+m+p,sgn,p);
}
}
int main() {
vector<double> u,v;
for (int i = 0; i < 256; i++) {
u.push_back(i);
v.push_back(i);
}
int sgn = 1;
int N = 256;
split_radix_rec(u.begin(),v.begin(),sgn,N);
return 0;
}
以下是我遇到的错误
main.cpp:93:21: error: 'std::vector<double>::iterator' has no member named 'begin'
6行93,94,95(从split_radix_rec函数中调用的三个split_radix_rec()函数)中的相同错误。这是一个更大的代码的一部分,所以我希望它适用于STL向量。我做错了什么?
答案 0 :(得分:3)
如错误所述,您正在begin()
上调用std::vector<double>::iterator
。
您应该在std::vector<double>
上调用它,以便它可以返回std::vector<double>::iterator
。
答案 1 :(得分:1)
r
,i
本身就是代码中的迭代器(开始)。
尝试:
split_radix_rec(r,i,sgn,m);
split_radix_rec(r+m,i+m,sgn,p);
split_radix_rec(r+m+p,i+m+p,sgn,p);
答案 2 :(得分:0)
有太多的代码可以为您提供简明的答案,但错误清楚地表明您在向量迭代器而不是向量上调用begin()
。这发生在split_radix_rec
递归调用。您可能已经打算这样做了:
split_radix_rec(r,i,sgn,m);
split_radix_rec(r+m,i+m,sgn,p);
split_radix_rec(r+m+p,i+m+p,sgn,p);