rubyXL（Errno :: ENOENT）

Question

我在使用rubyXL构建的爬虫时遇到问题。它正确遍历我的文件系统，但是我收到(Errno::ENOENT)错误。我检查了所有rubyXL代码，一切似乎都检查出来。我的代码附在下面 - 任何建议？

/Users/.../testdata.xlsx
/Users/.../moretestdata.xlsx
/Users/.../Lab 1 Data.xlsx
/Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:404:in `initialize': No such file or directory - /Users/Dylan/.../sheet6.xml (Errno::ENOENT)
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:404:in `open'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:404:in `block in decompress'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:402:in `upto'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:402:in `decompress'
    from /Users/Dylan/.rvm/gems/ruby-1.9.3-p327/gems/rubyXL-1.2.10/lib/rubyXL/parser.rb:47:in `parse'
    from xlcrawler.rb:9:in `block in xlcrawler'
    from /Users/Dylan/.rvm/rubies/ruby-1.9.3-p327/lib/ruby/1.9.1/find.rb:41:in `block in find'
    from /Users/Dylan/.rvm/rubies/ruby-1.9.3-p327/lib/ruby/1.9.1/find.rb:40:in `catch'
    from /Users/Dylan/.rvm/rubies/ruby-1.9.3-p327/lib/ruby/1.9.1/find.rb:40:in `find'
    from xlcrawler.rb:6:in `xlcrawler'
    from xlcrawler.rb:22:in `<main>'

---

require 'find'
require 'rubyXL'

def xlcrawler(path)
  count = 0
  Find.find(path) do |file|                                # begin iteration of each file of a specified directory
    if file =~ /\b.xlsx$\b/                                # check if a given file is xlsx format
      puts file                                            # ensure crawler is traversing the file system
      workbook = RubyXL::Parser.parse(file).worksheets     # creates an object containing all worksheets of an excel workbook
      workbook.each do |worksheet|                         # begin iteration over each worksheet
        data = worksheet.extract_data.to_s                 # extract data of a given worksheet - must be converted to a string in order to match a regex
        if data =~ /regex/
          puts file
          count += 1
        end      
      end
    end
  end
  puts "#{count} files were found"
end

xlcrawler('/Users/')

Answer 1

我在github上挖掘了rubyXL代码，看起来解压缩方法中存在一个错误。

  files['styles'] = Nokogiri::XML.parse(File.open(File.join(dir_path,'xl','styles.xml'),'r'))
  @num_sheets = files['workbook'].css('sheets').children.size
  @num_sheets = Integer(@num_sheets)

  #adds all worksheet xml files to files hash
  i=1
  1.upto(@num_sheets) do
    filename = 'sheet'+i.to_s # <----- BUG IS HERE
    files[i] = Nokogiri::XML.parse(File.open(File.join(dir_path,'xl','worksheets',filename+'.xml'),'r'))
    i=i+1
  end

这段代码假设有关excel中的工作表编号，这是不正确的。此代码只计算工作表数量，并以数字方式对其进行分配。但是，如果删除工作表，则创建新工作表，数字序列将被破坏。

如果您检查Lab Data 1.xlsx文件，如果您拉出vba开发人员窗口（按alt + F11），您将看到没有工作表6，您会看到类似

的内容

正如你所看到的那样，这种安排会打败for循环并在i = 6时导致异常。