我的应用程序中使用了以下类型的URL。
本地主机/管理/ userdetail / ID
本地主机/管理/ userdetail / ID /真
本地主机/管理/ userdetail / ID /真/成功
这是我的管理员控制器
bool inSaveAction,字符串状态是可选的
[Authorize]
public ActionResult UserDetail(string Id, bool inSaveAction, string status)
{
}
[HttpPost, Authorize, ValidateAntiForgeryToken]
public ActionResult SaveUserDetail(UserDetailViewModel viewModel)
{
User userToSave = new User();
AdminService.UpdateUser(userToSave);
//This is calling the above function as it sending all 3 params
return RedirectToAction("UserDetail", new { Id = viewModel.Id,
inSaveAction = true, status = "success" });
}
以下案例无效
@Html.ActionLink("DisplayName", "UserDetail", new { id = Model.Id })
在Global.asax
中 routes.MapRoute("UserDetail",
"UserDetail/{id}",
new
{
controller = "Admin",
action = "UserDetail",
id = UrlParameter.Optional
}
);
如何制作inSaveAction& status是我的UserDetail操作的可选参数吗?
答案 0 :(得分:9)
您缺少路线配置中的参数。为了使这个工作与不同的参数可选(如Phil Haack的帖子),你需要定义多个路线
routes.MapRoute("UserDetail-WithStatus",
"UserDetail/{id}/{inSaveAction}/{status}",
new
{
controller = "Admin",
action = "UserDetail",
// nothing optional
}
);
routes.MapRoute("UserDetail-WithoutStatus",
"UserDetail/{id}/{inSaveAction}",
new
{
controller = "Admin",
action = "UserDetail",
// nothing optional
}
);
routes.MapRoute("UserDetail-WithoutSaveAction",
"UserDetail/{id}",
new
{
controller = "Admin",
action = "UserDetail",
id = UrlParameter.Optional
}
);
然后创建链接:
@Html.ActionLink("Link", "Index", "Admin", new { id = 1, inSaveAction = true, success = "success" }, null)
您还需要将可选参数设置为可为空,否则如果缺少id或inSaveAction,您将获得异常。
public ActionResult UserDetail(int? id, bool? inSaveAction, string status)
{
}
答案 1 :(得分:1)
您可以使用here引入的方法。它允许您定义一个这样的路线
routes.MapRoute(name: "UserDetail-WithStatus",
url: "UserDetail/{id}/{inSaveAction}/{status}",
defaults: new
{
controller = "Admin",
action = "UserDetail",
// nothing optional
},
lookupParameters:new string[] { "id", "inSaveAction", "status" },
routeValueService: new RouteValueService()
);