Question

您好我正在尝试查询JPA上的一些数据，这是我的查询：

@Override
    public List<HorarioAtencion> findByPeriodo(Person person, int dia, int mes, int anno) {
        Query busqueda = em.createNativeQuery("Select * from HorariosAtencion where " +
                                              "idPerson = ?1 AND "+
                                              "DAY( fechaInicio) <= ?2 AND MONTH( fechaInicio ) <= ?3 AND YEAR( fechaInicio) <= ?4 AND "+
                                              "DAY( fechaFin) >= ?2 AND MONTH( fechaFin ) >= ?3 AND YEAR( fechaFin ) >= ?4 ORDER BY TIME(fechaInicio)", HorarioAtencion.class);
       busqueda.setParameter(1,person.getId());
       busqueda.setParameter(2, dia);
       busqueda.setParameter(3, mes);
       busqueda.setParameter(4, anno);
       return busqueda.getResultList();
    }

此查询返回结果，但会触发下一个异常：

Caused by: Exception [EclipseLink-6044] (Eclipse Persistence Services - 2.3.2.v20111125-r10461): org.eclipse.persistence.exceptions.QueryException
Exception Description: The primary key read from the row [ArrayRecord(
     => 1
     => 13
     => 2013-01-04 12:25:00.0
     => 2013-01-04 12:25:00.0
     => true
     => true
     => true
     => true
     => true
     => true
     => true)] during the execution of the query was detected to be null.  Primary keys must not contain null.
Query: ReadAllQuery(referenceClass=HorarioAtencion sql="Select * from HorariosAtencion where idPerson = ? AND DAY( fechaInicio) <= ? AND MONTH( fechaInicio ) <= ? AND YEAR( fechaInicio) <= ? AND DAY( fechaFin) >= ? AND MONTH( fechaFin ) >= ? AND YEAR( fechaFin ) >= ? ORDER BY TIME(fechaInicio)")

我不知道可能是什么问题：/

更新：

实体类的列定义：

private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Basic(optional = false)
    @Column(name = "id")
    private Integer id;

    @Basic(optional = false)
    @Column(name = "fechaInicio")
    @Temporal(TemporalType.TIMESTAMP)
    private Date fechaInicio;

    @Basic(optional = false)
    @Column(name = "fechaFin")
    @Temporal(TemporalType.TIMESTAMP)
    private Date fechaFin;

    @Basic(optional = false)
    @Column(name = "domingo")
    private boolean domingo;

    @Basic(optional = false)
    @Column(name = "lunes")
    private boolean lunes;

    @Basic(optional = false)
    @Column(name = "martes")
    private boolean martes;

    @Basic(optional = false)
    @Column(name = "miercoles")
    private boolean miercoles;

    @Basic(optional = false)
    @Column(name = "jueves")
    private boolean jueves;

    @Basic(optional = false)
    @Column(name = "viernes")
    private boolean viernes;

    @Basic(optional = false)
    @Column(name = "sabado")
    private boolean sabado;

    @JoinColumn(name = "idPersona", referencedColumnName = "id")
    @ManyToOne(optional = false)
    private Persona idPersona;

Answer 1

您使用的是什么数据库，以及它为列名返回了什么？

默认情况下，

EclipseLink 在较新版本中区分大小写，除非eclipselink.jpa.uppercase-column-names persistent属性设置为true。

如果将列名称定义为小写"ID"，则数据库将列名返回为大写"id"时，这可能是本机查询的问题。

尝试更改注释中的列定义以匹配数据库使用的内容，或者将属性添加为值true。

Answer 2

问题是eclipselink区分大小写。有一个“提示”可以解决这个问题。将以下内容放在persistence.xml文件中的properties元素之间：

<!-- Hint to solve "The primary key read from the row [DatabaseRecord(...)] during the execution of the query was detected to be null." errors.-->
<property name="eclipselink.jpa.uppercase-column-names" value="true"/>

这将以不区分大小写的方式处理列名并消除错误。

Answer 3

找到此帖子https://forums.oracle.com/thread/614380。

与postgres和EclipseLink有同样的问题。

解决方案：将主键列更改为大写：

从表格中选择ID 作为＆＃34; ID＆＃34; ，field1，field2，...，fieldn

Answer 4

在HorariosAtencion表null值的某个位置找到了与主键对应的字段。

Answer 5

...从行读取的主键[ArrayRecord（...

表示HorariosAtencion记录正常。有两个ID，两个日期和所有布尔值。 1可能是ID值。所以，我怀疑异常是指相关的 Persona实体。是否有Persona个空PK？

Answer 6

在HorariosAtencion的一个/多个主键上有/是空值 /假面。仔细检查你的数据库。

或者您需要设置角色ID而不是引用对象，尝试

public List<HorarioAtencion> findByPeriodo(Person person, int dia, int mes, int anno) {
    Query busqueda = em.createQuery("from HorariosAtencion where " +
                                          "idPerson = ?1 AND "+
                                          "DAY( fechaInicio) <= ?2 AND MONTH( fechaInicio ) <= ?3 AND YEAR( fechaInicio) <= ?4 AND "+
                                          "DAY( fechaFin) >= ?2 AND MONTH( fechaFin ) >= ?3 AND YEAR( fechaFin ) >= ?4 ORDER BY TIME(fechaInicio)", HorarioAtencion.class);
   busqueda.setParameter(1,person);
   busqueda.setParameter(2, dia);
   busqueda.setParameter(3, mes);
   busqueda.setParameter(4, anno);
   return busqueda.getResultList();
}

或

public List<HorarioAtencion> findByPeriodo(Person person, int dia, int mes, int anno) {
    Query busqueda = em.createNativeQuery("Select * from HorariosAtencion where " +
                                          "**idPerson.id** = ?1 AND "+
                                          "DAY( fechaInicio) <= ?2 AND MONTH( fechaInicio ) <= ?3 AND YEAR( fechaInicio) <= ?4 AND "+
                                          "DAY( fechaFin) >= ?2 AND MONTH( fechaFin ) >= ?3 AND YEAR( fechaFin ) >= ?4 ORDER BY TIME(fechaInicio)", HorarioAtencion.class);
   busqueda.setParameter(1,person.getId());
   busqueda.setParameter(2, dia);
   busqueda.setParameter(3, mes);
   busqueda.setParameter(4, anno);
   return busqueda.getResultList();
}

Answer 7

我有同样的问题，我找到了一个解决方案，尝试从em.createNativeQuery行删除“HorarioAtencion.class。

JPA查询的奇怪错误

7 个答案: