我正在尝试使用Clojure core.logic从地图中提取数据。这段代码就像我想要的那样:
(run 10 [q]
(fresh [?id ?type ?name]
(membero ?type [:t2 :t1])
(== q [?id ?name])
(membero {:id ?id :type ?type :name ?name}
[
{:id 1 :type :t1 :name "one"}
{:id 2 :type :t2 :name "two"}
])))
=> ([2 "two"] [1 "one"])
但是,如果我向地图添加一些其他元素,则无法匹配:
(run 10 [q]
(fresh [?id ?type ?name]
(membero ?type [:t2 :t1])
(== q [?id ?name])
(membero {:id ?id :type ?type :name ?name}
[
{:id 1 :type :t1 :name "one" :other1 :o1}
{:id 2 :type :t2 :name "two" :other2 :o2}
])))
我理解为什么matcho
不起作用,因为地图不再相同。我的问题是,我怎样才能改变它以便它再次起作用?如何让它仅匹配地图中的某些键,或者如何使其匹配地图可能具有的任何随机键?
编辑:
我使用patial-map
(感谢https://github.com/clojure/core.logic/pull/10)
(run 10 [q]
(fresh [?id ?type ?name]
(membero ?type [:t2 :t1])
(== q [?id ?name])
(membero (partial-map {:id ?id :type ?type :name ?name} )
[
{:id 1 :type :t1 :name "one" :other1 :o2}
{:id 2 :type :t2 :name "two" :other2 :o1}
])))
但是我发现应该使用featurec
代替partial-map
。我的新问题:如何更改此问题以使用featurec
?
答案 0 :(得分:6)
回答我自己的问题:
以下是工作代码:
(run 10 [q]
(fresh [?id ?type ?name ?pm]
(membero ?type [:t2 :t1])
(== q [?id ?name])
(featurec ?pm {:id ?id :type ?type :name ?name} )
(membero ?pm
[
{:id 1 :type :t1 :name "one" :other1 :o2}
{:id 2 :type :t2 :name "two" :other2 :o1 :another :ao2}
{:id 3 :type :t3 :name "three" :other2 :o1 :another :ao1}
]))))
此代码允许我从地图中提取值,但只关注真正重要的键。其余的键值对将被忽略。