Question

我正在尝试使用以下代码在星期四和星期五发出通知：这段代码是星期四

Calendar updateTime = Calendar.getInstance();
updateTime.set(Calendar.HOUR_OF_DAY, 14);
updateTime.set(Calendar.MINUTE, 44);
updateTime.set(Calendar.SECOND, 0);
updateTime.set(Calendar.DAY_OF_WEEK, 5);
if(updateTime.before(new GregorianCalendar())){
    updateTime.add(GregorianCalendar.DAY_OF_MONTH, 7);
}
Intent intent = new Intent(context, Alarm4.class);
intent.putExtra(ONE_TIME, Boolean.TRUE);
PendingIntent pi = PendingIntent.getBroadcast(context, 0, intent, 0);
AlarmManager alarmManager = (AlarmManager) getSystemService(ALARM_SERVICE);
alarmManager.set(AlarmManager.RTC_WAKEUP, updateTime.getTimeInMillis(), pi);

但是，如果时间已超过通知时间，则此代码无法直接弹出通知。

我错过了什么？

Answer 1

这样做。

           if (updateTime.getTimeInMillis() < System.currentTimeMillis()

                || updateTime.before(new GregorianCalendar())) {
            updateTime.set(Calendar.HOUR_OF_DAY, hourOfDay + 24);
            updateTime.add(GregorianCalendar.DAY_OF_MONTH, 7);
        }

并创建一个类来设置警报。

        public class setAlarm {

Context context;

public setAlarm(Context c) {
    // TODO Auto-generated constructor stub
    this.context = c;
}

public void settingAlarm(Calendar calendar, int counter) {
    Intent intent = new Intent(context, AlarmReceiver.class);
    PendingIntent pendingIntent = PendingIntent.getBroadcast(context,
            counter, intent, PendingIntent.FLAG_UPDATE_CURRENT);
    AlarmManager alarmManager = (AlarmManager) context
            .getSystemService(Context.ALARM_SERVICE);
    alarmManager.setRepeating(AlarmManager.RTC_WAKEUP,
            calendar.getTimeInMillis(), AlarmManager.INTERVAL_DAY,
            pendingIntent);
}

}

和Alarm BroadCastReceiver是公共类AlarmReceiver扩展了BroadcastReceiver {

private NotificationManager manager;
private int NOTIFICATION_ID;

@Override
public void onReceive(Context context, Intent intent) {
    // TODO Auto-generated method stub
    Toast.makeText(context, "Alarm Received", Toast.LENGTH_LONG).show();
    manager = (NotificationManager) context
            .getSystemService(Context.NOTIFICATION_SERVICE);
    Notification notification = new Notification(R.drawable.ic_launcher,
            "Food Time", System.currentTimeMillis());
    Intent intent2 = new Intent(context, MainActivity.class);
    PendingIntent pendingIntent = PendingIntent.getActivity(context, 0,
            intent2, PendingIntent.FLAG_UPDATE_CURRENT);
    notification.setLatestEventInfo(context, "FoodTime",
            "Click to View your food", pendingIntent);
    notification.flags |= Notification.FLAG_AUTO_CANCEL;

    notification.sound = Uri
            .parse("android.resource://"
                    + "com.technogalax.sixsmallmealaday.alarm" + "/"
                    + R.raw.nsound);

    manager.notify(NOTIFICATION_ID, notification);

}

}

Answer 2

显然，你的代码还可以，但已经完成了一半。现在，您必须创建一个BroadcastReceiver，您必须从中设置通知。您可以浏览此article，这篇文章对您有所帮助。我想在这里提一下，它会为用户设置单一警报，而不是重复。要重复，您必须使用public void setRepeating (int type, long triggerAtMillis, long intervalMillis, PendingIntent operation)而不是public void set (int type, long triggerAtMillis, PendingIntent operation)。它仍然会定期重复。</ p>

在我对您的特定重复类型的想法中，您可以以不同的方式进行排列。最初使用public void set (int type, long triggerAtMillis, PendingIntent operation)将警报设置为第二天（在第二天检查警报后）。这将非常简单。当系统广播报警时，您的BroadcastReceiver将被呼叫。在onRecieve()您的BroadcastReceiver中，设置通知并设置第二天的闹钟（在第二天检查闹钟后）。通过这种方式，总循环过程将在您的控制之下，您可以轻松地为其设置任何逻辑。

特定工作日的Android通知会直接发生

2 个答案: