Question

我正在尝试修复已经开始失败的MS Access查询。这是由几年前离开的其他人建造的系统，所以我正在倒退去理解它。失败的部分是一个连接其他两个子查询的查询。

如果我在查询连接上运行'SELECT *'，它会毫无问题地返回数据。但是，只要我尝试定义一个特定的字段，它就会失败并显示无效的消息“查询过于复杂”。

所以，这会返回数据没问题：

SELECT * FROM 530a_WIPIncomeShareByResource 
INNER JOIN 510_AllInvoicesCreditsInvWIP 
ON [530a_WIPIncomeShareByResource].WIPDocApplicable 
     = [510_AllInvoicesCreditsInvWIP].No_
WITH OWNERACCESS OPTION;

但是，如果我从连接中的两个查询中的任何一个定义任何字段，那么它会出错，从而给出“查询过于复杂”的错误。所以，这失败了，例如：

SELECT [510_AllInvoicesCreditsInvWIP].Status 
FROM 530a_WIPIncomeShareByResource 
INNER JOIN 510_AllInvoicesCreditsInvWIP 
ON [530a_WIPIncomeShareByResource].WIPDocApplicable 
     = [510_AllInvoicesCreditsInvWIP].No_ 
WITH OWNERACCESS OPTION;

我已经分别检查了连接中引用的两个子查询（530a_WIPIncomeShareByResource和510_AllInvoicesCreditsInvWIP），这些子查询都执行正常和返回数据。然而，加入这两者并不是。

我对Access经验不足，所以无论如何都会感激不尽！

嗨，这是子查询的代码：

530a_WIPIncomeShareByResource：

SELECT [502_WIP_DocApplicable].No_ AS [Resource No_], 
[502_WIP_DocApplicable].[Posting Date], 
[502_WIP_DocApplicable].WIPDocApplicable, 
[502_WIP_DocApplicable].WIPOpen, 
Sum(IIf([Work Type code]<>"WRITEOFF" 
        And [Type]<>3 
        And [Work Type code]<>"DISBURSE" 
        And [Work Type code]<>"DIRRESP" 
        And [Work Type code]<>"TAXJ"
        And [Work Type code]<>"INVMON" 
        And [Work Type code]<>"CUST"
        And [NAVTCIWORKTYPE-FEETYPE.Disbursement]<>1,[WIPValue],0)) AS QualWIP, 
Sum(IIf([Work Type code]="WRITEOFF",[WIPValue],0)) AS NonQualWOWIP, 
Sum(IIf([Work Type code]="DISBURSE" 
        Or [Work Type code]="XTNLPERCEN"
        Or [Type]=3 
        Or [NAVTCIWORKTYPE-FEETYPE.Disbursement]=1,[WIPValue],0)) AS DISBURSE, 
Sum(IIf([Work Type code]="DIRRESP" 
        Or [Work Type code]="TAXJ" 
        Or [Work Type code]="INVMON"
        Or [Work Type code]="CUST",[WIPValue],0)) AS FIXEDFEE,
Sum([502_WIP_DocApplicable].WIPValue) AS TotalWIP
FROM [NAVTCIWORKTYPE-FEETYPE] 
INNER JOIN 502_WIP_DocApplicable 
ON [NAVTCIWORKTYPE-FEETYPE].Code = [502_WIP_DocApplicable].[Work Type Code]
GROUP BY [502_WIP_DocApplicable].No_, 
         [502_WIP_DocApplicable].[Posting Date],
         [502_WIP_DocApplicable].WIPDocApplicable, 
         [502_WIP_DocApplicable].WIPOpen
WITH OWNERACCESS OPTION;

和第二个：

510_AllInvoicesCreditsInvWIP

SELECT [510_AllInvoicesCredits].[Job No_], 
[510_AllInvoicesCredits].No_, 
[510_AllInvoicesCredits].[Invoice Date1] AS [Invoice Date],  
[510_AllInvoicesCredits].Status, 
[510_AllInvoicesCredits].[Invoice No_], 
[510_AllInvoicesCredits].REVERSED, 
[510_AllInvoicesCredits].[Reversal Document No_], 
[510_AllInvoicesCredits].[Reversal Document Date], 
[510_AllInvoicesCredits].Reference, 
IIf([DocType]="Credit",[TotalBill],([TotalBill]-[FTRaised]+(-
    (IIf(IsNull([FTWO]),0,
     IIf([TotalBill]<=-0.01,-[FTWO],[FTWO]))))-
    (IIf([TotalBill]<0,-[DISBURSE],[DISBURSE]))-
    (IIf([TotalBill]<0,-[FIXEDFEE],[FIXEDFEE]))-
    (IIf([TotalBill]<0,-[XTNLPERCENSHARE],[XTNLPERCENSHARE]))-
    (IIf([TotalBill]<0,-[FIXEDFEESHARE],[FIXEDFEESHARE])))) AS IncomeToAlloc, 
[510_AllInvoicesCredits].TotalBill, 
[510_AllInvoicesCredits].XTNLPERCENSHARE, 
[510_AllInvoicesCredits].FIXEDFEESHARE, 
[520a_WIPAnalysis1_WIP].QualWIP, 
[520a_WIPAnalysis1_WIP].NonQualWOWIP, 
[520a_WIPAnalysis1_WIP].DISBURSE, 
[520a_WIPAnalysis1_WIP].TotalWIP, 
[510_AllInvoicesCredits].FTRaised AS FTR, 
IIf(IsNull([FTWO]),0,IIf([TotalBill]<0,-[FTWO],[FTWO])) AS FTWO1, 
[520a_WIPAnalysis1_WIP].GenCFWIPUsed, 
[510_AllInvoicesCredits].GenCF AS GenCFRaised, 
[510_AllInvoicesCredits].WOPROVRaised AS WOPROVR, 
[520b_WIPAnalysis2_FT].WOPROVWO AS WOPROVUsed, 
[520a_WIPAnalysis1_WIP].FIXEDFEE, 
[510_AllInvoicesCredits].DocType, 
[510_AllInvoicesCredits].Doc
FROM (510_AllInvoicesCredits LEFT JOIN 520a_WIPAnalysis1_WIP 
ON [510_AllInvoicesCredits].No_ = [520a_WIPAnalysis1_WIP].WIPDocApplicable) 
LEFT JOIN 520b_WIPAnalysis2_FT 
ON [510_AllInvoicesCredits].No_ = [520b_WIPAnalysis2_FT].FTDocApplicable
WHERE ((([510_AllInvoicesCredits].REVERSED)<>1))
ORDER BY [510_AllInvoicesCredits].[Invoice Date1]
WITH OWNERACCESS OPTION;

整个Access系统是一层一层的查询。破译真的很头疼！但是，上面运行得很好。

MS Access查询：定义一个字段显示“查询太复杂”使用*是好的

0 个答案: