我想编写一个select查询来获取从子级到父级的完整路径:
| Unique Id | Child Code | Parent Code |
| X | 9 | 7 |
| Y | 7 | 6 |
| Z | 6 | 5 |
| A | 5 | NULL |
| B | 11 | 33 |
| C | 33 | 22 |
| D | 22 | NULL |
如果选择的代码是9,则查询应返回其所有父项,结果如下:9-7-6-5 ......
如果选择的代码是11,则查询应返回:11-33-22 ....
感谢。
答案 0 :(得分:2)
尝试此查询
SELECT *
FROM (
SELECT
@r AS _id,
(SELECT @r := parent_code FROM mytable WHERE unique_id = _id) AS parent_id,
@l := @l + 1 AS lvl
FROM
(SELECT @r := 9, @l := 0) vars,
mytable m
WHERE @r <> 0) T1
JOIN mytable T2
ON T1._id = T2.id
ORDER BY T1.lvl DESC;
答案 1 :(得分:1)
使用NULL
父值:
SELECT *
FROM <table_name>
ORDER BY COALESCE(<parent_id>,<id>), <id>), category_parent_id IS NOT NULL
使用ZERO
父值:
SELECT *
FROM <table_name>
ORDER BY COALESCE((SELECT NULLIF(<parent_id>,0)), <id>), NULLIF(<parent_id>,0) IS NOT NULL