Question

我想做这样的事情

$x = 630;
$y = 10;

while ($y < $x){
// do something
$y+10;
}

当我使用$y++它正在工作并添加+1时，但是+10它不起作用。但我需要进行+10步。有什么指针吗？

Answer 1

在您的代码中，您没有递增$y：$y+10返回$y加10的值，但您需要将其指定给$y

您可以通过多种方式实现：

$y = $y + 10;
$y += 10;

示例：

$x = 630;
$y = 10;
while ($y < $x){
    // do something
    $y = $y + 10;
}

Answer 2

这是因为$ y ++相当于$ y = $ y + 1;您没有在$ y中分配新值。请尝试

$y += 10;

OR

$y = $y + 10;

Answer 3

// commenting the code with description
$x = 630; // initialize x
$y = 10;  // initialize y

while ($y < $x){ // checking whether x is greater than y or not. if it is greater enter loop
// do something
$y = $y+10; // you need to assign the addition operation to a variable. now y is added to 10 and the result is assigned to y. please note that $y++ is equivalent to $y = $y + 1
}

当Loop到达数量时

3 个答案: