我正在尝试在Python上创建一个与PHP的htmlentities
和html_entity_decode
类似的html实体编码器/解码器,它通常作为一个独立的脚本运行:
我的意见
Lorem ÁÉÍÓÚÇÃOÁáéíóúção @#$%*()[]<>+ 0123456789
python decode.py
输出:
Lorem ÁÉÍÓÚÇÃOÁáéíóúção @#$%*()[]<>+ 0123456789
现在,如果我将其作为 Autokey 脚本运行,我会收到此错误:
Script name: 'html_entity_decode'
Traceback (most recent call last):
File "/usr/local/lib/python2.7/dist-packages/autokey/service.py", line 454, in execute
exec script.code in scope
File "<string>", line 40, in <module>
File "/usr/local/lib/python2.7/dist-packages/autokey/scripting.py", line 42, in send_keys
self.mediator.send_string(keyString.decode("utf-8"))
File "/usr/lib/python2.7/encodings/utf_8.py", line 16, in decode
return codecs.utf_8_decode(input, errors, True)
UnicodeEncodeError: 'ascii' codec can't encode characters in position 6-12: ordinal not in range(128)
我做错了什么?这是脚本:
import htmlentitydefs
import re
entity_re = re.compile(r'&(%s|#(\d{1,5}|[xX]([\da-fA-F]{1,4})));' % '|'.join(
htmlentitydefs.name2codepoint.keys()))
def html_entity_decode(s, encoding='utf-8'):
if not isinstance(s, basestring):
raise TypeError('argument 1: expected string, %s found' \
% s.__class__.__name__)
def entity_2_unichr(matchobj):
g1, g2, g3 = matchobj.groups()
if g3 is not None:
codepoint = int(g3, 16)
elif g2 is not None:
codepoint = int(g2)
else:
codepoint = htmlentitydefs.name2codepoint[g1]
return unichr(codepoint)
if isinstance(s, unicode):
entity_2_chr = entity_2_unichr
else:
entity_2_chr = lambda o: entity_2_unichr(o).encode(encoding,
'xmlcharrefreplace')
def silent_entity_replace(matchobj):
try:
return entity_2_chr(matchobj)
except ValueError:
return matchobj.group(0)
return entity_re.sub(silent_entity_replace, s)
text = clipboard.get_selection()
text = html_entity_decode(text)
keyboard.send_keys("%s" % text)
我在Gist https://gist.github.com/607454上找到了它,我不是作者。
答案 0 :(得分:3)
查看回溯可能的问题是你将一个unicode字符串传递给keyboard.send_keys,它需要一个UTF-8编码的字节串。然后autokey尝试解码失败的字符串,因为输入是unicode而不是utf-8。这看起来像是autokey中的一个错误:它不应该尝试解码字符串,除非它们真的是普通的(字节)字符串。
如果这个猜测是正确的,你应该能够通过确保将unicode实例传递给send_keys来解决这个问题。尝试这样的事情:
text = clipboard.get_selection()
if isinstance(text, unicode):
text = text.encode('utf-8')
text = html_entity_decode(text)
assert isinstance(text, str)
keyboard.send_keys(text)
断言不是必需的,但是是一个方便的健全性检查,以确保html_entity_decode做正确的事。
答案 1 :(得分:2)
问题是输出:
clipboard.get_selection()
是一个unicode字符串。
解决问题替换:
text = clipboard.get_selection()
由:
text = clipboard.get_selection().encode("utf8")