我是这个林间空地的新手(也是这个论坛的新手),想知道你们中的任何人是否可以帮助我:
我必须获取用户从chooserbutton中选择的文件名,并将其作为字符串发送给函数。不幸的是,我一直在收到这个恼人的错误:
Gtk-CRITICAL **:IA__gtk_file_chooser_get_uri:断言`GTK_IS_FILE_CHOOSER(选择器)'失败
我认为这是由于小部件的错误使用造成的。有人可以帮我解决这个问题吗?源代码如下所示,正如您所见,它来自https://live.gnome.org/Glade/Tutorials处的Glade-GTK教程。
该程序是一个简单的2按钮窗口:第一个按钮是filechooser按钮,第二个按钮是单击时调用“clica”功能的标准按钮。它应该显示用户通过文件选择器按钮选择的文件名,但这是错误发生的时间。
测试源(只是为了弄清楚如何使用小部件):
#include <gtk/gtk.h>
int
main( int argc,
char **argv )
{
GtkBuilder *builder;
GtkWidget *window;
GError *error = NULL;
/* Init GTK+ */
gtk_init( &argc, &argv );
/* Create new GtkBuilder object */
builder = gtk_builder_new();
/* Load UI from file. If error occurs, report it and quit application.
* Replace "tut.glade" with your saved project. */
if( ! gtk_builder_add_from_file( builder, "tut.glade", &error ) )
{
g_warning( "%s", error->message );
g_free( error );
return( 1 );
}
/* Get main window pointer from UI */
window = GTK_WIDGET( gtk_builder_get_object( builder, "window1" ) );
/* Connect signals */
gtk_builder_connect_signals( builder, NULL );
/* Destroy builder, since we don't need it anymore */
g_object_unref( G_OBJECT( builder ) );
/* Show window. All other widgets are automatically shown by GtkBuilder */
gtk_widget_show( window );
/* Start main loop */
gtk_main();
return( 0 );
}
void clica(GtkFileChooser *filechooserbutton1){//this button was inserted through Glade
char cNome[250];
*cNome = gtk_file_chooser_get_uri(GTK_FILE_CHOOSER(filechooserbutton1));
printf("\n%s", cNome);
}
Glade文件:
<?xml version="1.0" encoding="UTF-8"?>
<interface>
<requires lib="gtk+" version="2.24"/>
<!-- interface-naming-policy project-wide -->
<object class="GtkWindow" id="window1">
<property name="can_focus">False</property>
<child>
<object class="GtkHBox" id="hbox1">
<property name="visible">True</property>
<property name="can_focus">False</property>
<child>
<object class="GtkFileChooserButton" id="filechooserbutton1">
<property name="visible">True</property>
<property name="can_focus">False</property>
</object>
<packing>
<property name="expand">True</property>
<property name="fill">True</property>
<property name="position">0</property>
</packing>
</child>
<child>
<object class="GtkButton" id="button1">
<property name="label" translatable="yes">button</property>
<property name="visible">True</property>
<property name="can_focus">True</property>
<property name="receives_default">True</property>
<property name="use_action_appearance">False</property>
<signal name="clicked" handler="clica" swapped="no"/>
</object>
<packing>
<property name="expand">True</property>
<property name="fill">True</property>
<property name="position">1</property>
</packing>
</child>
</object>
</child>
</object>
</interface>
答案 0 :(得分:1)
04/01/2013更新(现在我们有林间空地文件)
我们现在可以看到您使用了错误对象的信号。你连接了你的&#34; clica&#34;回调&#34;点击&#34; GtkButton&#34; button1&#34;的信号,而不是将其连接到GtkFileChooserButton&#34; filechooserbutton1&#34;。
原始回答: 没有林间空地文件,我们无法看到您连接的信号,而不是它们连接的信号。但是你有可能不遵循信号的原型。如果断言失败,那意味着在你的回调中,你认为第一个参数是GtkFileChooser是另一回事。