Question

我有一个包含多个列的表，其中一列是日期列（data1）。

使用的mysql查询是

SELECT * from leads WHERE data1 between date_sub(now(),INTERVAL 1 WEEK) and now()

然后我们从每一行获取数据，运行一些计算并将其存储为单独的变量。

我现在想将这些数据与上周的数据（在同一张表中）进行比较，即通过更改SELECT查询。

让我扩大......

查询从表中获取本周数据：

$sqld = "SELECT * from leads WHERE data1 between date_sub(now(),INTERVAL 1 WEEK) and now()";

现在我们开始提取数据

$result = mysql_query($sqld) or die(mysql_error());

$num_rows = mysql_num_rows($result);

while($row = mysql_fetch_array($result))
{
      $referred = $referred + $row['referred'];
      $invalidated = $invalidated + $row['invalidated'];
      $tobequalified = $tobequalified + $row['tobequalified'];
}

（以上只是我们需要运行以演示的计算片段。）

现在我们根据这周的数据显示结果

          <h4>Totals for this week</h4>

            <table class="table stat-table">
                <tbody>
                    <tr>
                        <td class="value"><? echo $num_rows; ?></td>
                        <td class="full">Total leads</td>
                    </tr>
                    <tr>
                        <td class="value"><? echo $referred; ?></td>
                        <td class="full">Referred</td>
                    </tr>
                    <tr>
                        <td class="value"><? echo $invalidated; ?></td>
                        <td class="full">Invalidated</td>
                    </tr>
                    <tr>
                        <td class="value"><? echo $tobequalified; ?></td>
                        <td class="full">To be qualified</td>
                    </tr>

                </tbody>
            </table>

我现在想更改上面的$ sqld查询以选择表格中属于上周的行，运行上面相同的计算并显示结果下面我们可以比较两者。

            <h4> Totals for last week</h4>


            <table class="table stat-table">
                <tbody>
                    <tr>
                        <td class="value"><? echo $num_rows; ?></td>
                        <td class="full">Total leads</td>
                    </tr>
                    <tr>
                        <td class="value"><? echo $referred; ?></td>
                        <td class="full">Referred</td>
                    </tr>
                    <tr>
                        <td class="value"><? echo $invalidated; ?></td>
                        <td class="full">Invalidated</td>
                    </tr>
                    <tr>
                        <td class="value"><? echo $tobequalified; ?></td>
                        <td class="full">To be qualified</td>
                    </tr>

                </tbody>
            </table>

有没有办法实现这一点而无需复制所有内容并更改$ sqld查询？

Answer 1

$result1 = mysql_query("SELECT * FROM leads");
$result2 = mysql_query("SELECT * FROM other table");
$arr1 = new Array();
$arr2 = new Array();

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
  {
  $arr1['FirstName'] = $row['your column name'];
  }

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
  {
  $arr2['FirstName'] = $row['your column name'];
  }

现在你有两个数组（$ arr1和$ arr2），你可以根据需要进行比较......

Answer 2

我认为您可以创建一个重复数据的函数，并使用某个参数调用它来更改查询，如下所示

somefunction("Previous");
somefunction();

function somefunciton($query = "current") {
    if($query == "Current")
        $sqld = "SELECT * from leads WHERE data1 between date_sub(now(),INTERVAL 1 WEEK) and now()";
    else
        $sqld = "SELECT * from leads WHERE data1 between date_sub(now(),INTERVAL 2 WEEK) and (now(),INTERVAL 1 WEEK)";
    $result = mysql_query($sqld) or die(mysql_error());

    $num_rows = mysql_num_rows($result);

    while($row = mysql_fetch_array($result))
    {
          $referred = $referred + $row['referred'];
          $invalidated = $invalidated + $row['invalidated'];
          $tobequalified = $tobequalified + $row['tobequalified'];
    }
    <h4>Totals for this week</h4>

        <table class="table stat-table">
        <tbody>
            <tr>
            <td class="value"><? echo $num_rows; ?></td>
            <td class="full">Total leads</td>
            </tr>
            <tr>
            <td class="value"><? echo $referred; ?></td>
            <td class="full">Referred</td>
            </tr>
            <tr>
            <td class="value"><? echo $invalidated; ?></td>
            <td class="full">Invalidated</td>
            </tr>
            <tr>
            <td class="value"><? echo $tobequalified; ?></td>
            <td class="full">To be qualified</td>
            </tr>

        </tbody>
        </table>
}

切换mysql查询以比较结果

2 个答案: