Question

我正在尝试创建一个自提交选择框，每次从下拉列表中选择时，都会将用户带到新页面。目前它没有做太多任何事情，只需带我到“//website.com/listing/?col=1&brand=”，没有任何id将其指向正确的URL。

任何想法，我做错了吗？

<form method="post" action="">
<select onchange="this.form.submit()">
<? foreach($arrayCollection['brands'] as $id => $name):value ?>
    <option value="//website.com/listing/?col=1&brand=<?php echo $id; ?>">
       <?php echo $name; ?>
   </option>
<? endforeach; ?>
</select>
</form>

Answer 1

由于您已在jquery中标记：

试试这个：

<script type="text/javascript" src="jquery-1.2.6.pack.js"></script>
    <form method="post" action="">
    <select id="selectDropDown">
    <? 
    $arrayCollection['brands'] = array(0=>'zero',1=>'first',2=>'second',3=>'three',4=>'four');
    foreach($arrayCollection['brands'] as $id => $name):value ?>
        <option value="<?php echo $id; ?>">
           <?php echo $name; ?>
       </option>
    <? endforeach; ?>
    </select>
    </form>
    <script>
    $('#selectDropDown').change(function(){
    window.location= '//website.com/listing/?col=1&brand='+$(this).val();
    });
    </script>

Answer 2

你可以尝试这个：

<form method="post" action="">
<select onchange="this.form.submit()">
<?php foreach($arrayCollection['brands'] as $id => $name):value ?>
//^^^---------------------missed it
    <option value="//website.com/listing/?col=1&brand=<?php echo $id; ?>">
       <?php echo $name; ?>
   </option>
<?php endforeach; ?>
//^^^---------------------missed it
</select>
</form>

可能对foreach doc有用：http://php.net/manual/en/control-structures.foreach.php

选择框自动提交与php变量

2 个答案: