Question

我在SQLiteOpenHelper类中创建了数据库。我还在其他活动Button click中的InsertActivity.java事件中插入了数据库。现在，当我在listview上显示数据时，生成了两个相同的条目。如何在listview中显示不同的记录？

ListActivity.java

public class ListActivity extends Activity {
    ListView lv;
    ArrayList<String> items = new ArrayList<String>();
    ArrayList<String> items_id = new ArrayList<String>();
    dbhelper dh;
    SQLiteDatabase db;
    int index_id;
    Button btn;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_list);
        Button btn;
        btn = (Button)findViewById(R.id.newProjectlist);
        btn.setOnClickListener(new OnClickListener() {

            public void onClick(View v) {
                // TODO Auto-generated method stub


                    Intent intent= new Intent(ListActivity.this,NewProject.class);
                startActivity(intent);
            }
        });  
        lv = (ListView)findViewById(R.id.projectListView);
        setUpList();
        dh = new dbhelper(this);

        Cursor c = getAllData();
        showAllData(c);  
        registerForContextMenu(lv);      
    }

  @Override
    public void onCreateContextMenu(ContextMenu menu, View v,
            ContextMenuInfo menuInfo) {
        // TODO Auto-generated method stub
        super.onCreateContextMenu(menu, v, menuInfo);

        if(v.getId() == R.id.projectList){
            menu.setHeaderIcon(R.drawable.ic_launcher);
            menu.setHeaderTitle("Record List");
            menu.add(0,1,menu.NONE,"Delete Record");
            menu.add(0,2,menu.NONE,"Show Record");
        }
    }

    @Override
public boolean onContextItemSelected(MenuItem item) {
    // TODO Auto-generated method stub
        int itemId = item.getItemId();
        if(itemId == 1)
        {
            AdapterView.AdapterContextMenuInfo menuinfo = (AdapterContextMenuInfo) item.getMenuInfo();
            int poistion = menuinfo.position;
            String id_string = items_id.get(poistion);
            long id = Long.valueOf(id_string);

            //menuinfo = (AdapterContextMenuInfo) item.getMenuInfo();
            //index_id = menuinfo.position;
            deleteUserData(index_id);
            items_id.remove(poistion);
        }
        if(itemId == 2){
            AdapterView.AdapterContextMenuInfo menuinfo;
            menuinfo = (AdapterContextMenuInfo) item.getMenuInfo();
            index_id = menuinfo.position;
            editUserData(index_id);
        }
    return super.onContextItemSelected(item);
}

    private void editUserData(int indexid) {
        // TODO Auto-generated method stub
        String user_id = items_id.get(indexid);
        Intent intEdit = new Intent(ListActivity.this, MainActivity.class);
        intEdit.putExtra("EditID", user_id);
        startActivityForResult(intEdit, 1);
    }

    private void deleteUserData(int indexid) {
        // TODO Auto-generated method stub
//      String user_id = items_id.get(indexid);
        //Toast.makeText(getApplicationContext(), "id " + user_id, 1).show();
        db = dh.getWritableDatabase();
        db.delete("timer","_ID" + "=" + indexid, null);
        finish();
//      Toast.makeText(getApplicationContext(), "Record deleted successfully", 1).show();
    }

    private void showAllData(Cursor c) {
        // TODO Auto-generated method stub
        while(c.moveToNext())
        {
            int id = c.getInt(0);
            String name = c.getString(1);
            String timerpoint1 = c.getString(2);
            String timerpoint2 = c.getString(3);
            String timerpoint3 = c.getString(4);
            String servicetime1 = c.getString(5);
            String servicetime2 = c.getString(6);
            items.add("" + name);
            items_id.add(""+id);
        }
        setUpList();
    }

    private Cursor getAllData() {
        // TODO Auto-generated method stub
        db = dh.getReadableDatabase();
        //String sortorder = dh.Name + "DESC";
    //  String query ="SELECT DISTINCT name FROM timer";
    //  Cursor c = db.rawQuery(query, null);
    //   if (c != null) {
    //            c.moveToFirst();
    //        }
//      String[] cols = new String[] {"name"};
        Cursor c = db.query(true, "timer",null,null,null,null,null,null,null);   
        //Cursor cur = db.query(Distinct,"timer", null, null, null, null, null, null, null);
        startManagingCursor(c);
    //  Cursor c=db.rawQuery("select distinct Name from timer;",null);
        return c;   
        }     
    private void setUpList() {
        // TODO Auto-generated method stub
        lv.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1,items));
    }   

    }

Answer 1

尝试使用GROUP BY。如果您仍然找不到所需的结果，请检查您是否在任何地方执行sqlite查询时出错，并告诉我。

SELECT Name 
FROM timer
GROUP BY Name

Answer 2

如何避免在ListView中重复输入???

避免重复使用addRecord方法（）。因为当你在addRecord（）中调用insert（）时，只需一次在onClick（）中定义addRecord（），最后你就避免在Listview中使用相同的记录条目。

如何在android中使用sqlite数据库显示唯一数据？

2 个答案: