Question

我想在轨道，地理编码器或任何其他有效方式的两个经度纬度点之间获得行驶距离。有吗？

Answer 1

Google Maps API v3 documentation指定原点或目的地（或路标）可以是地址或google.maps.LatLng。要获得两个经度/纬度点之间的行驶距离，请将其作为google.maps.LatLng对象传递到request。

相关问题：total distance and time for all waypoints in google maps v3

proof of concept fiddle

代码段（基于the example in the documentation）：

function initMap() {
  var directionsService = new google.maps.DirectionsService;
  var directionsDisplay = new google.maps.DirectionsRenderer;
  var map = new google.maps.Map(document.getElementById('map'), {
    zoom: 7,
    center: {
      lat: 41.85,
      lng: -87.65
    }
  });
  directionsDisplay.setMap(map);
  // New York, NY, USA (40.7127837, -74.0059413)
  var start = new google.maps.LatLng(40.7127837, -74.0059413);
  //Baltimore, MD, USA (39.2903848, -76.6121893)
  var end = new google.maps.LatLng(39.2903848, -76.6121893);
  calculateAndDisplayRoute(start, end, directionsService, directionsDisplay);
}

function calculateAndDisplayRoute(start, end, directionsService, directionsDisplay) {
  directionsService.route({
    origin: start,
    destination: end,
    travelMode: google.maps.TravelMode.DRIVING
  }, function(response, status) {
    if (status === google.maps.DirectionsStatus.OK) {
      var totaldistance = 0;
      var route = response.routes[0];
      // display total distance information.
      for (var i = 0; i < route.legs.length; i++) {
        totaldistance = totaldistance + route.legs[i].distance.value;
      }
      document.getElementById('distance').innerHTML += "<p>total distance is " + (totaldistance / 1000).toFixed(2) + " km</p>";
      directionsDisplay.setDirections(response);
    } else {
      window.alert('Directions request failed due to ' + status);
    }
  });
}
google.maps.event.addDomListener(window, "load", initMap);

html,
body,
#map {
  height: 100%;
  width: 100%;
  margin: 0px;
  padding: 0px
}

<script src="https://maps.googleapis.com/maps/api/js"></script>
<div id="distance"></div>
<div id="map"></div>

Answer 2

    var R = 6371; 
    var dLat = toRad(lat2-lat1);
    var dLon = toRad(lon2-lon1); 

    var dLat1 = toRad(lat1);
    var dLat2 = toRad(lat2);

    var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
            Math.cos(dLat1) * Math.cos(dLat1) * 
            Math.sin(dLon/2) * Math.sin(dLon/2); 
    var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a)); 
    var d = R * c;
    alert(d);

    function toRad(Value) {
     /** Converts numeric degrees to radians */
     return Value * Math.PI / 180;

Answer 3

如果您不想依赖（精心制作的）Google API或受限于API限制，我会发现另一种选择：OpenStreetMap＆＃39; s osrm-project。

就我而言，我需要将近200,000间房屋的最近行驶距离检索到某个兴趣点。

获得两个经度纬度点之间的行驶距离

3 个答案: