有没有办法告诉Cython编译器param是函数。像
这样的东西 cpdef float calc_class_re(list data, func callback)
答案 0 :(得分:32)
应该是不言自明的..? :)
# Define a new type for a function-type that accepts an integer and
# a string, returning an integer.
ctypedef int (*f_type)(int, str)
# Extern a function of that type from foo.h
cdef extern from "foo.h":
int do_this(int, str)
# Passing this function will not work.
cpdef int do_that(int a, str b):
return 0
# However, this will work.
cdef int do_stuff(int a, str b):
return 0
# This functio uses a function of that type. Note that it cannot be a
# cpdef function because the function-type is not available from Python.
cdef void foo(f_type f):
print f(0, "bar")
# Works:
foo(do_this) # the externed function
foo(do_stuff) # the cdef function
# Error:
# Cannot assign type 'int (int, str, int __pyx_skip_dispatch)' to 'f_type'
foo(do_that) # the cpdef function