Question

我正在尝试为SRT格式创建语法：

以下是srt文件的示例：

1
00:00:02,218 --> 00:00:04,209
[SHELDON SPEAKING IN MANDARIN]

2
00:00:04,721 --> 00:00:05,745
No, it's:

3
00:00:05,922 --> 00:00:07,913
[SPEAKING IN MANDARIN]

4
00:00:09,392 --> 00:00:11,383
[SPEAKING IN MANDARIN]

5
00:00:13,430 --> 00:00:15,193
What's this?

6
00:00:16,266 --> 00:00:18,029
That's what you did.

7
00:00:18,201 --> 00:00:22,467
I assumed, as in a number of languages,
that the gesture was part of the phrase.

8
00:00:22,639 --> 00:00:25,233
- Well, it's not.
- Why am I supposed to know that?

9
00:00:25,408 --> 00:00:28,900
As teacher, it's your obligation
to separate your personal idiosyncrasies...

10
00:00:29,079 --> 00:00:30,512
...from the subject matter.

11
00:00:31,081 --> 00:00:33,845
- I'm glad you decided to learn Mandarin.
- Why?

326
00:18:56,818 --> 00:19:00,720
Actually, I've heard
far too much about Schrödinger's cat.

327
00:19:01,623 --> 00:19:03,022
Good.

328
00:19:09,131 --> 00:19:11,895
All right, the cat's alive.
Let's go to dinner.

329
00:19:12,000 --> 00:19:15,072
Download Movie Subtitles Searcher from www.OpenSubtitles.org

这是我的antlr语法（v.3.4）。

grammar Exp;


parse
    :  (SUBTITLE)+
    ;

SUBTITLE
    : i=ID NL 
      t1=Timestamp SPACE ARROW SPACE t2=Timestamp NL 
      txt1 = TEXT

        {
            System.out.println("id="+$i); 
            System.out.println("t1= "+$t1); 
            System.out.println("t2= "+$t2);
            System.out.println("txt1= "+$txt1);

        }
    ;

TEXT 
    : ((TextLine NL NL)|(TextLine NL TextLine NL NL))
    ;

ID
    : DIG+
    ;

ARROW
    : '-->'
    ;

Timestamp
    : DIG DIG ':' DIG DIG ':' DIG DIG ',' DIG DIG DIG
    ;

TextLine
  :  ~('\r' | '\n')*
  ;

NL
  :  '\r'? '\n'
  |  '\r'
  ;

fragment
DIG 
    : '0'..'9'
    ;

fragment
SPACE
    :   ' ' | '\t'
    ;

我的简单代码：

String input = IOUtils.toString(Test.class.getResourceAsStream("/subtitles.srt"));
ExpLexer lexer = new ExpLexer(new ANTLRStringStream(input));
CommonTokenStream stream = new CommonTokenStream(lexer);
ExpParser parser = new ExpParser(stream);
parser.parse();

如果在文件末尾我有两条新线，几乎所有东西都能完美运行。如果不是，我收到了这个错误：

line 1484:0 no viable alternative at character '<EOF>'

任何建议如何更改我的语法更灵活？接受最后将是一个新线，两个新线或更多。

Answer 1

原因是TEXT最后需要2个新行。

您可以尝试从TEXT删除一个尾随NL，而不是SUBTITLE之间的分隔符。

类似的东西：

parse
    :  SUBTITLE (NL SUBTITLE)*
    ;

是的，TEXT是否只能有一两行？

Answer 2

你正在使用过多的词法规则。

尝试这样的事情：

grammar T;

options {
  output=AST;
}

tokens {
  BLOCKS;
  BLOCK;
  TIME_RANGE;
  LINES;
  LINE;
  WORD;
}

parse
 : LineBreak* blocks LineBreak* EOF -> blocks
 ;

blocks
 : block (LineBreak LineBreak+ block)* -> ^(BLOCKS block+)
 ;

block 
 : Number Spaces? LineBreak time_range LineBreak text_lines -> ^(BLOCK Number time_range text_lines)
 ;

time_range
 : Time Spaces? Arrow Spaces? Time Spaces? -> ^(TIME_RANGE Time Time)
 ;

text_lines
 : line (LineBreak line)* -> ^(LINES line+)
 ;

line
 : Spaces? word (Spaces word)* Spaces? -> ^(LINE word+)
 ;

word
 : (Other | Number | Dashes | Arrow)+ -> WORD[$text]
 ;

Time      : Number ':' Number ':' Number ',' Number;
Arrow     : '-->';
Dashes    : '-'+;
Number    : '0'..'9'+;
LineBreak : '\r'? '\n' | '\r';
Spaces    : (' ' | '\t')+;
Other     : . ;

将解析输入：

1
00:00:02,218 --> 00:00:04,209
[A B C]

2
00:00:04,721 --> 00:00:05,745
-- Line 1
-- Line 2



3
00:00:05,922 --> 00:00:07,913
mu --> MU

进入以下AST：

（点击图片查看大图）

修改

我在文本中有数字和冒号时有问题。 '第1季第15集：'或'“我会在11:00给你打电话。维多利亚。” '试图修改你的例子，但没有成功。

未经测试，但我认为这应该可行：只需在{/ 1}}规则中的第一个冒号之后将所有设为可选。在规则的最后，检查Time中的最后Number是否匹配。如果没有，请将令牌类型更改为Time。

Other

在我的语法</eof>中没有可行的替代品'<eof>'

2 个答案:

修改