ID Name Address Acc_Number BookingNo Amt
1 MERY Kollam 111111111 NULL 1000
2 Jos Kochi 111111111 c/01 NULL
输出
ID Name Address Acc_Number BookingNo Amt
1 MERY Kollam 111111111 c/01 1000
答案 0 :(得分:2)
我认为使用Acc_Number自动加入同一个表应该实现
SELECT
a.ID,
a.Name,
a.Address,
a.Acc_Number,
COALESCE(a.BookingNo, b.BookingNo) as BookingNo,
COALESCE(a.Amt, b.Amt) As Amt
FROM TableA a
JOIN TableA b
ON a.Acc_Number = b.Acc_Number
答案 1 :(得分:0)
SELECT top 1 t1.ID,t1.Name,
t1.Address,
t1.Acc_Number,
COALESCE(t1.BookingNo, t2.BookingNo) as 'BookingNo',COALESCE(t1.Amt, t2.Amt) as 'Amt'
FROM testtable1 t1 JOIN testtable1 t2
ON t1.Acc_Number = t2.Acc_Number and t1.NAME!=t2.NAME